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Probability of getting 3 heads = \(4C3* (0.4)^3* (0.6) = 0.1536\)

micv
If a coin is tossed, the probability of getting heads is 0.4. On 4 tosses of a coin, what is the probability of getting exactly 3 heads?
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nick1816 why do we multiple with 4C3? Can you explain this? Is it cause we need 3 heads? and then we are multiplying it with the probabilities?
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micv
If a coin is tossed, the probability of getting heads is 0.4. On 4 tosses of a coin, what is the probability of getting exactly 3 heads?

P(H) = 0.4
i.e. P(T) = 1-0.4 = 0.6

Choose which 3 show head out of 4 coins in \(4C3\) ways
Probability of those chosen 3 coins showing head = \(0.4^3\)
Probability of 4th coins showing Tail = \(0.6\)

Probability of Exactly 3 H = P (3H 1T) = \(4C3*(0.4)^3*0.6 = 4*(0.4)^3*0.6\)


micv Bunuel Please include the following options in the question

A) (0.4)^3*0.6
B) 4*(0.4)^3*0.6
C) 3*(0.4)^3*0.6
D) 4*(0.6)^3*0.4
E) 3*(0.6)^3*0.4

Answer: Option B
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{HHHT}, {HHTH}, {HTHH} and {THHH}

Since we can get Head on any of 3 turns out of 4, you gotta multiply by 4C3.

micv
nick1816 why do we multiple with 4C3? Can you explain this? Is it cause we need 3 heads? and then we are multiplying it with the probabilities?
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