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05 Oct 2020, 07:26
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (02:36) correct
59%
(02:19)
wrong
based on 27
sessions
History
Date
Time
Result
Not Attempted Yet
A 4-digit number is randomly selected that has all even digits. What is the probability that this number is divisible by 8?
(A) 1/8
(B) 1/4
(C) 2/5
(D) 3/16
(E) 8/25
(A) 1/8
(B) 1/4
(C) 2/5
(D) 3/16
(E) 8/25
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05 Oct 2020, 09:37
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I think the answer is B.
1. 4 event digits --> 2, 4, 6, 8
2. Numbers ending in 2,6,8 are not divisible 8 (check with numbers)
3. Number must end in 4, meaning 6 (3*2*1) possible numbers that end in 4.
4. Total possibilities is 4*3*2*1 = 24
5. 6/24 = 1/4
1. 4 event digits --> 2, 4, 6, 8
2. Numbers ending in 2,6,8 are not divisible 8 (check with numbers)
3. Number must end in 4, meaning 6 (3*2*1) possible numbers that end in 4.
4. Total possibilities is 4*3*2*1 = 24
5. 6/24 = 1/4
05 Oct 2020, 14:55
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4 digit integers, all digits even= 4*5*5*5 = 500
Half of above are divisible by 4= 250
Half of above are divisible by 8= 125
P= 125/500 = 1/4
Ans B
Half of above are divisible by 4= 250
Half of above are divisible by 8= 125
P= 125/500 = 1/4
Ans B
