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Solution


Given:
    • Each outcome of a fair coin has equal probability

To find:
    • Probability of atleast one heads

Approach and Working:
    • Total number of outcomes = 2 * 2 = 4, which are {HH, HT, TH, TT}
      o Among these 3 outcomes have atleast one heads, {HH, TH, HT}

    • Therefore, the probability of atleast one heads = \(\frac{3}{4}\)

Hence, the correct answer is Option E

Answer: E

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Given that A fair coin is tossed twice, and we need to find What is the probability that the coin will land heads at least once on two tosses?

P(At least one Head) = 1 - P(0 head) = 1 - P(TT)
= 1 - \(\frac{1}{2}\) * \(\frac{1}{2}\) (As P(T) in each toss = \(\frac{1}{2}\) )
= 1 - \(\frac{1}{4}\) = \(\frac{3}{4}\)

So, Answer will be E
Hope it helps!

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Watch the following video to MASTER Probability with Coin Toss Problems

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