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Bunuel
For what value of K, the number 7236K2 is divisible by 8?

(A) 9
(B) 7
(C) 5
(D) 4
(E) 3

Divisibility tets of 8: Last three digits of Number must be divisible by 8

i.e. for 7236K2 to be divisible by 8, 6K2 must be divisible

Checking Options

(A) 9 i.e. we must check 692, but 692 is NOT divisible by 8 so OUT
(B) 7 i.e. we must check 672, and 672 is divisible by 8 so CORRECT
(C) 5
(D) 4
(E) 3

Answer: Option B

E is also divisible ???

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