The profit P, in dollars, for any given month at a certain company is

Question

The profit P, in dollars, for any given month at a certain company is defined by P= I − C, where I represents total income, in dollars, and C represents total costs, in dollars, for the month. For each of the first 4 months of the year, C = I + 32,000; and for each of the next 3 months, I = C + 36,000. If I = C + 10,000 for each of the 5 remaining months of the year, what was the company's total profit for the 12-month year?

(A) $10,000
(B) $30,000
(C) $40,000
(D) $50,000
(E) $70,000

PS01080.02

(A) $10,000 
(B) $30,000
(C) $40,000 
(D) $50,000 
(E) $70,000

PS01080.02

nick1816 · Accepted Answer

Profit for each of first 4 Months = I-C= I-I-32000 = -32000 or 32000 (loss)

Profit for each of next 3 months = I-C = C+3600 - C = 36000

Profit for each of last 5 months = I-C = C+10000-C = 10000

Net profit for 12 months =  + +   = -32000 + 3*(36000-32000) +50000 = 30000$

yashikaaggarwal · Answer

Answer is supposedly 30,000
Company profit= I-C
I is the income/month
C is the cost/month
Profit/Loss For first 4 months
C=I+32000
-32000=I-C  
Loss for first 4 month = 32000*4=128000-----(1)

Profit/Loss For next 3 months
I=C+32000
36000=I-C  
Profit for next 3 month = 36000*3=108000-----(2)

Profit/Loss For next 5 months
I=C+10000
10000=I-C  
Profit for next 5 month = 10000*5=50000-----(3)

Total Profit/Loss=
= -128000+108000+50000
= 30000

IOC is B

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dave13 · Answer

Cost= I+32 * ( 4 months) = I +128 Income = C+36 * (3 months) = C+108 Income = C+10 * (5 months) = C+150 Profit = I -C 158-128 = 30

Ravixxx · Answer

Fast solution requires to eliminate all the elements that are not helpful

SOLUTION:
 4 Months*(-32) = -128 
 3 Months*(+36) = 108  
 5 Months*(+10) = 50

Revenue-Cost =

108+50-128 = 158-128 = 30

ANSWER (B)

ScottTargetTestPrep · Answer

Let’s express I in terms of C for the first 4 months of the year. For each of these 4 months, I = C - 32,000. Therefore, the total profit for the year is:

P = 4(C - 32,000) + 3(C + 36,000) + 5(C + 10,000) - 12C

P = 4C - 128,000 + 3C + 108,000 + 5C + 50,000 - 12C

P = 30,000

Answer: B

perfectreview · Answer

Formula for profit (P) = I - C

Profit for the first 4 months = 4*  = 4*  = -128000

Profit for the next 3 months = 3*  = 3*  = 108000

Profit for the next 5 months = 5*  = 5*  = 50000

Total profit = -128000 + 108000 + 50000 = 30000

Gmat20201 · Answer

Soln:

Given P= I − C

- The first 4 months of the year, C = I + 32,000 --> 4C=4I + 128000 ---> 4I- 4C = -128000
- For each of the next 3 months, I = C + 36,000 --> 3I=3C +108000 ---> 3I-3C = 108000
- For 5 remaining months , I = C + 10,000 --> 5I=5C + 50000 ---> 5I- 5C = 50000

P = I- C therefore, Total Profit for the year = (-128000+108000+50,000)=30000

Ans choice B

Hope this helps

Neha2404 · Answer

It is given 
P (Profit)= I( Income)-C (Cost)

First 4 month profit. (A) =-32000*4 = -128000
Next 3 month profit. (B) =36000*3. =108000
Remaining 5 month profit (C). =10000*5 =50000

Total profit. 12 month profit. =A+B+C. =30000

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kawal27 · Answer

first 4 months c=I+320000 means C-I=-32000 for each month total 4*-32000 = -128000
next 3 months I = C + 36,000 means I-C=36000 FOR each month means total 3*36000=108000
remaining 5 months I=C+10000 means I-C=10000 FOR EACH MONTH means total 5*10000=50000

12 months profit = 50000+108000-128000=30000
ANS:B

CrackverbalGMAT · Answer

SOLUTION:

A NEW OG 2021 QUESTION

P= I − C is given

For each of first 4 months C = I + 32,000 (given) => Profit for first 4 months (P) = I-(I+32000)

= -32000 (Negative sign indicates a loss)
Total loss in the first 4 months = 4*32000

=$ - 128,000

For each of the next 3 months, I = C + 36,000

=>C=I-36000

=>Profit for each of the next 3 months (P) = I-(I-36000)

=36000

Total profit for the 3 months = 3*36,000

=$108,000

For each of the 5 remaining months of the year, I = C + 10,000

=> C=I -10,000

Profit for the 5 remaining months of the year(P) = I-(I-10,000)

=10,000

Total profit in these 5 months = 5*10,000
= $50,000

Thus, the total profit for 12 months

=-128000 + 108000 + 50,000

= $30,000 (OPTION B)

Hope this helps

Devmitra Sen(Math)

GMATinsight · Answer

Answer: Option B

Video solution by  GMATinsight

https://www.youtube.com/watch?v=MByoVBusxpw

Jainam24 · Answer

We can divide all values by 1000 i.e. look at 32000 as 32 and so on. Why? Because the ans options also can be divided by 1000(friendly nos) and it is relatively easy to calculate 2 digit nos then 5 digit nos. 
We can bypass the algebra just by looking at the problem in parts: 
Part 1: 4 months- Loss of 32*4=128
Part 2:3 months- Profit of 36*3=108 
Part3: 5 months- Profit of 10*5=50

Therefore total profit is: 50+108-128=30 i.e. 30000

Option B is the ans

nimishb23 · Answer

It is given to us that P=I-C.

First 4 months : It is given to us C=I+32,000, however we must see the original formula given. If we are to isolate C, we will get C=I-P, therefore 32,000 will be negative. 
4*-32,000=-128,000

Next 3 months:  I=C+36,000. P will be positive in this case because when we isolate I in the formula we will get I=C+P. 
3*36,000=108,000

Last 5 months:  I=C+10000. Same logic as the previous part.
5*10,000=50,000

-128,000+108,000+50,000=30000

Hence option B

The profit P, in dollars, for any given month at a certain company is

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The profit P, in dollars, for any given month at a certain company is

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