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skim
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GMAT TIGER
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skim
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Thanks, GT and amolsk11.

Reference is made to the first question. Although I understand:

12 < x .........i.

I don't understand:

Also x is:
x < 0 ...... ii


Would appreciate clarification to the above. Thanks.
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In inequalities like these I find at first the limits of range, when x=y. In this case it will be:
1. 4/x = 1/3 i.e. when x=12. Then, if you want to lessen 4/x, you should INCREASE x, as x is denominator (try picking numbers, such as 16 and 8 for example and you will see the right way). Thus, the range of possible values are x>12.

2. IMO, for the 2nd question the answer is -12 < x < 0
If 4/x < -1/3 what is the possible range of values for x?
First of all, x is only negative, i.e. x<0. Otherwise, 4/x will be positive and >-1/3
Then, one of the margins for values of x is when 4/x = -1/3, i.e. when x=-12. If we want 4/x to become less, we should INCREASE the denominator, try again picking some numbers such as -8 (-4/8 < -1/3) and -16 (-4/16 > -1/3). But we can increase x only till 0. Thus, the range of solutions is -12 > x >0.
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Hi Gmat Tiger and amolsk11,
Can you pls. clarify my doubt regarding your solution for the second inequality.

You guys arrived at
(12+X)/3X <0
Q1. Can we cross multiply without considering the sign in the inequality. I generallt refrain myself from multiplying or diving an inequality.
Q2. If we know that x is -ve why are we not inverting the sign of the inequality ?
Q3. If we pretend that we are not bothered of the sign then i think cross multiplyinh is not allowed across inequalities.

Pls. help
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The OA for the second inequality question is -12 < x < 0



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