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Bunuel
One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.07 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?

(A) $7.15
(B) $8.87
(C) $28.96
(D) $35.57
(E) $39.92

Two of the costs are fixed:
$1.07 for operating-system overhead
$4.35 for the mounting of a data tape

So, let's focus on $0.023 per millisecond of computer time.
Rewrite as: $0.023 for every 0.001 of a second
Multiply both numbers by 1000 to get: $23.00 for every 1 second
Multiply both numbers by 1.5 to get: $34.50 for 1.5 seconds
So, the computer time costs $34.50

$34.50 + $4.35 + $1.07 = MORE THAN $35.57
Answer: E

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Good question


First notice that the major cost component is the computer time. For a program that runs for 1.5 seconds the cost will be 1.5 seconds * ($0.023 per millisecond)

Converting 1.5 seconds to milliseconds \(= \frac{1.5}{0.001}\) = 1500
The cost for computer time is 1500*$0.023.

Approximating: Notice that 1500*$.020 is $30 and 1500*$0.002 is $3 this eliminates A,B and C. The precise value is over $33
Now adding the two remaining cost components, i.e system overhead of $1.07 and mounting tape cost of $4.35 brings us over $38 which eliminates D.

The only answer left is E
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Bunuel
One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.07 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?

(A) $7.15
(B) $8.87
(C) $28.96
(D) $35.57
(E) $39.92

Since 1.5 seconds = 1.5 x 1000 = 1500 milliseconds, the total cost is:

1.07 + 0.023(1500) + 4.35 = $39.92

Answer: E
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Bunuel
One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.07 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?

(A) $7.15
(B) $8.87
(C) $28.96
(D) $35.57
(E) $39.92
Solution:

The cost of 1 run of a program that requires 1.5 seconds (or 1500 milliseconds) of computer time is:

1.07 + 1500 x 0.023 + 4.35 = 1.07 + 34.50 + 4.35 = $39.92

Answer: E
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Bunuel
One millisecond is 0.001 of a second. The costs for a single run of a computer program are $1.07 for operating-system overhead, $0.023 per millisecond of computer time, and $4.35 for the mounting of a data tape. What is the total of these three costs for 1 run of a program that requires 1.5 seconds of computer time ?

(A) $7.15
(B) $8.87
(C) $28.96
(D) $35.57
(E) $39.92

determine the number of milliseconds is 1.5 seconds by using the information given in the question that 0.001 second = 1 millisecond

1.5 seconds * 1 millisecond / 0.001 seconds
\(= \frac{1.5}{0.001}\) milliseconds

= 1500 milliseconds

to find the total cost to run 1 program that requires 1.5 seconds of computer time then
\(1.07+0.023*(1500)+4.35\)
\(= 39.92\)

thus answer is E
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