The question asks which expression MUST be odd for every integer x. The
key principle here is:
Even + Odd = Always OddEven + Even = Always EvenOdd × Anything = Could be eitherLet's test each choice:
A) 2x +
2 =
2(x +
1) — This has a factor of
2, so it's ALWAYS EVEN. Eliminate.
B) 4x +
3 — Since
4 times any integer is always even,
4x is even. Adding
3 (an odd number) to an even number ALWAYS gives an odd number. This MUST be odd.
This is our answer!But let's confirm by eliminating the rest:
C) 12x -
6 =
6(
2x -
1) — This has a factor of
6, so it's ALWAYS EVEN. Eliminate.
D) 13x — If x =
1, this is
13 (odd). If x =
2, this is
26 (even). So it's
NOT always odd. Eliminate.
E) 14x =
2(
7x) — This has a factor of
2, so it's ALWAYS EVEN. Eliminate.
Answer: BKey Insight: The general principle to remember:
Even number + Odd number = ALWAYS Odd. In
4x +
3, the
4x part is always even (any number multiplied by an even number is even), and
3 is always odd. So the result must always be odd.
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