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rahulgmat2014
How we have calculated Factor of 28 ? 4 and 14 are not prime .. is it correct to show factor as non prime number ?

Factor of an integer is not necessarily a prime number.

A divisor of an integer \(n\), also called a factor of \(n\), is an integer which evenly divides \(n\) without leaving a remainder. In general, it is said \(m\) is a factor of \(n\), for non-zero integers \(m\) and \(n\), if there exists an integer \(k\) such that \(n = km\).

So, the factors of 28 are 1, 2, 4, 7, 14, and 28.

Theory on Number Properties: math-number-theory-88376.html
Divisibility tips: divisibility-multiples-factors-tips-and-hints-174998.html?hilit=divisibility%20tips

DS Divisibility/Multiples/Factors questions to practice: search.php?search_id=tag&tag_id=354
PS Divisibility/Multiples/Factors questions to practice: search.php?search_id=tag&tag_id=185[/textarea]

Hope it helps.
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So when it says "unique factors' - that does not equal prime?
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phferr1984
So when it says "unique factors' - that does not equal prime?

No, Unique factors = different factors.
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Is there a faster way to find ALL the factors of a number?
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Is there a faster way to find ALL the factors of a number?

Finding the Number of Factors of an Integer

First make prime factorization of an integer \(n=a^p*b^q*c^r\), where \(a\), \(b\), and \(c\) are prime factors of \(n\) and \(p\), \(q\), and \(r\) are their powers.

The number of factors of \(n\) will be expressed by the formula \((p+1)(q+1)(r+1)\). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: \(450=2^1*3^2*5^2\)

Total number of factors of 450 including 1 and 450 itself is \((1+1)*(2+1)*(2+1)=2*3*3=18\) factors.

2. Properties of Integers




5. Divisibility/Multiples/Factors



For other subjects:
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A perfect number is defined as one for which the sum of all the unique factors less the number itself is equal to the number. For instance, 6 is a perfect number, because the factors of 6 (apart from 6 itself) are 1, 2 and 3, and \(1 + 2 + 3 = 6\). Which of the following is also a perfect number?

A. 12
B. 20
C. 28
D. 48
E. 60
This is question is simple to calculate for all , To calculate sum of factors except the number , we calculate sum of all factors - the number.

Sum of all factors of a number is given by if a number is P= a^n * b^m * c^k. Sum of all factors of P = (1 + a ..... a^n) (1+b+b^2 .... b^m )(1+c + c^2+....c^k)

so 28 will have (1+ 2 + 4) (1+ 7) = 56 sum of factors ,excluding number will be 28, so the perfect number.
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I have edited the question and the solution by adding more details to enhance its clarity. I hope it is now easier to understand.
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I like the solution - it’s helpful.
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I like the solution - it’s helpful.
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I don’t quite agree with the solution. Poor example. I thought multiplying all factors results in the number 1*2*3=6.
It should use a different example. Too easy to mistake with 1*2*3=6.
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Condemned13
I don’t quite agree with the solution. Poor example. I thought multiplying all factors results in the number 1*2*3=6.
It should use a different example. Too easy to mistake with 1*2*3=6.

Please read carefully. The question explicitly says sum, not product.

A perfect number is defined as a number for which the sum of all its unique positive factors, excluding the number itself, is equal to the number. For example, 6 is a perfect number because its factors, apart from 6 itself, are 1, 2, and 3, and their sum is 1 + 2 + 3 = 6. Which of the following numbers is also a perfect number?

If you still read that as multiplication, that’s your problem, not a flaw in the example.
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