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Updated on: 10 Nov 2023, 10:38
Originally posted by averagedude23 on 10 Nov 2023, 10:16.
Last edited by averagedude23 on 10 Nov 2023, 10:38, edited 1 time in total.
Last edited by averagedude23 on 10 Nov 2023, 10:38, edited 1 time in total.
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Today a certain cinema multiplex has exactly two showings (an early showing and a late showing) for each of five films (Films A, B, C, D, and E). All of these showings occur after noon, and each showing consists of the film only, with no previews, announcements, or advertisements. The following gives the duration of each film and the start time for each showing:
Statement: The early showing of Film 1 overlaps with at least part of both showings of Film 2.
Select for 1 and for 2 the options that complete the statement so that it is accurate of the showings listed in the information provided. Make only two selections, one in each column.
- Film A (90 minutes); 3:45 and 5:30
Film B (100 minutes); 1:30 and 7:15
Film C (105 minutes); 2:00 and 6:00
Film D (115 minutes); 5:00 and 8:00
Film E (125 minutes); 12:15 and 7:00
Statement: The early showing of Film 1 overlaps with at least part of both showings of Film 2.
Select for 1 and for 2 the options that complete the statement so that it is accurate of the showings listed in the information provided. Make only two selections, one in each column.
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1 = D, 2 = A
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10 Nov 2023, 10:35
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averagedude23
The duration of first movie should fill up the gap between two shows of second movie. So, film 2 will be one which has one of the least gap between the two shows.
Let us test the least first: Film A (90 minutes); 3:45 and 5:30
So the first show ends at 3:45 + 90 min = 5:15, and second show starts at 5:30.
Now, we check for any of the films that have their first show at 5:15 and 5:30 both.
Film D runs for 115 minutes at starts at 5:00, so it will run from 5:00 to 6:55.
So, 1 is film D and 2 is Film A.
10 Nov 2023, 10:36
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