For a circle with center point P cord XY is the perpendicular bisector

Question

https://gmatclub.com/forum/download/file.php?id=20548 For a circle with center point P, cord XY is the perpendicular bisector of radius AP (A is a point on the edge of the circle). What is the length of cord XY? (1) The circumference of circle P is twice the area of circle P. (2) The length of Arc XAY = \frac{2\pi}{3} . Untitled.png How come the answer is D? I have drawn these pictures as they were not provided with the questions. Even though with my guess work I have selected A which is incorrect. Can someone please let me know how to solve this? Also, I understand this will include a concept of 30-60-90 degree triangle - any idea which angles to assign 30 and 60 degrees?

Bunuel · Answer

https://gmatclub.com/forum/download/file.php?id=16528 For a circle with center point P, cord XY is the perpendicular bisector of radius AP (A is a point on the edge of the circle). What is the length of cord XY? From the diagram and the stem: AZ=ZP=r/2. In a right triangle ZPX ratio of ZP to XP is 1:2, hence ZPX is a 30-60-90 right triangle where the sides are in ratio: 1:\sqrt{3}:2 . The longest leg is ZX which corresponds with \sqrt{3} and is opposite to 60 degrees angle. Thus 2\pi{r}=2*\pi{r^2} --> r=1 --> XZ=\frac{\sqrt{3}}{2} --> XY=2*XZ=\sqrt{3} . Sufficient. (2) The length of Arc XAY = \frac{2\pi}{3} --> \frac{2\pi}{3}=\frac{120}{360}*2\pi{r} --> r=1 , the same as above. Sufficient. Answer: D. Chord.PNG

enigma123 · Answer

Sorry Bunuel - in your explanation, how come longest leg be ZX? I think it should be XP because that's opposite to 90 degree angle. Also, do you mind telling me how did you find out which side will correspond to 60 degree and 30 degree angle?

Bunuel · Answer

XP is hypotenuse, which obviously is the  longest side  but the  longest leg  is ZX (so the second longest side).

In a right triangle where the angles are 30°, 60°, and 90° the sides are always in the ratio  1 : \sqrt{3}: 2 . Notice that the smallest side (1) is opposite the smallest angle (30°), and the longest side (2) is opposite the largest angle (90°). Since the ratio of the leg ZP to the hypotenuse XP is 1:2, then ZP (the shortest side) corresponds to 1 and thus is the opposite of the smallest angle 30°, which means that another leg ZX corresponds to  \sqrt{3} .

Hope it's clear.

enigma123 · Answer

Sorry Bunuel - still struggling. How did you get XZ = sqrt3/2? Apologies for been a pain.

Bunuel · Answer

It's not a problem at all.

Since  \frac{XZ}{XP}=\frac{\sqrt{3}}{2}  (from 30°, 60°, and 90° right triangle ratio) and  XP=r=1  then  \frac{XZ}{1}=\frac{\sqrt{3}}{2}  --> XZ=\frac{\sqrt{3}}{2} .

Hope it's clear.

keenys · Answer

Hi Bunuel,

How did you assume ZPX is a 30-60-90 right triangle just from the ratio of ZP to XP (1:2). How can we assume in any triangle if the two sides are in the ratio 1:2, it will be a 30-60-90 triangle?

I thought we have to know we have to know that the triangle is 30-60-90 triangle beforehand to calculated the third side based on the ratio of two given sides.

Bunuel · Answer

Notice that since XY is the perpendicular to AP, then  ZPX is a right triangle with right angle at Z . So, we have that side:hypotenuse=1:2, which means that we have 30-60-90 triangle, where the ratio of the sides is  1:\sqrt{3}:2 .

keenys · Answer

Thanks for you reply Bunuel.

However, I still did not understand. Here we have angle XZP=90, XP=r and ZP=r/2.

We do not know that the other angles are 60 and 30 respectively. How can we use the ratio of two sides not three to conclude that it is a 30-60-90 triangle?

Should we know beforehand that it is a 30-60-90 triangle to use two sides to calculate the third one?

Bunuel · Answer

When we know two sides in a right triangle the third one is fixed.

We have side:hypotenuse=1x:2x --> third side =  \sqrt{(2x)^2-x^2}=\sqrt{3}*x , so the sides are in the ratio:  1:\sqrt{3}:2  --> 30-60-90 triangle.

Does this make sense?

keenys · Answer

Thanks Bunuel. Now it makes complete sense.

I missed the last part in calculating the third side using Pythagoras.

obs23 · Answer

I wonder if this is just today...that I am looking at this perfectly clear explanation and still do not get it. I did a couple of minutes later. So first of - thanks for detailed explanations Bunuel and others. I just wanted to add that (2x)^2-x^2 = 3x^2 for those who look at the formula with a predetermined mind so focused on that formula and as a result forget to calculate this basic stuff, perhaps wondering where that \sqrt{3}*x came from. It is possible it is just me, but it often appears to me that it is not. This is one of those..."duuuhhh"s

maaadhu · Answer

Bunuel,

If 2 pi r = 2 pi r^2

then either r=0 or r=1

Since radius is always +ve, its safe to assume that r=1. Is that correct?

Bunuel · Answer

Yes, because we obviously have a circle.

damamikus · Answer

Hey!

Could someone please check my calculations? I keep getting a wrong answer (I tried to solve it in a slightly different way but nonetheless the solution should be the same) for statement 1:

so, according to statement 1 --> 2pir=2pir² <=> r=1 ; for the following calculations, please see the attached image below.

(1) m°+n°=90° --> n°=90°-m°
(2) w°+p°=90°
(3)n°+p°=90°

--> (1) in (2): 90°-m°+p°=90° --> m°=p°, similarly: n°=w° ----> AXZ and XZB are similar triangles, hence, their side ratios will be equal.
--> (XZ/0.5)=(0.75/XZ) <=>2XZ=(3/4XZ) <=> XZ²=3/8 <=> XZ=0.5(3/2)^(1/2) --> XZ=2XZ=(3/2)^(1/2)

I tried the calculations again and again, but i keep getting the same wrong answer and not 3^(1/2). What did I do wrong? I know that the 30-60-90 approach is easier and probably quicker but I am still confused about what error I made in my calculations/ approach. If someone can help, please do so

Max

Attachments

chord-problem.jpg [ 34.19 KiB | Viewed 28963 times ]

Max

Bunuel · Answer

\frac{XZ}{AZ} = \frac{ZB}{XZ}  -->  AZ = 0.5  and  ZB = 1.5 , not 0.75.

\frac{XZ}{0.5} = \frac{1.5}{XZ}  -->  XZ^2 = \frac{3}{4}  -->  XZ=\frac{\sqrt{3}}{2} .

Hope it helps.

damamikus · Answer

Thanks a lot Bunuel! I totally missed that number-error!

adymehta29 · Answer

hi bunuel ! can u please explain the 2nd condition how did we get 120 degree ?

Bunuel · Answer

https://gmatclub.com/forum/download/file.php?id=16528 
The central angle which subtends arc XAY is angle XPY, which is 60+60=120 degrees.

Hope it's clear.

lalania1 · Answer

Hi Bunuel,

What formula have you applied to make statement 2 sufficient. Could you please explain. thanks!

(2) The length of Arc XAY = 2pi/3 --> \frac{2\pi}{3}=\frac{120}{360}*2\pi{r} --> r=1, the same as above. Sufficient.

For a circle with center point P cord XY is the perpendicular bisector

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