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![If x and y are integers and[m] |x| + y =0[/m], what is the value of x?](/forum/styles/gmatclub_light/imageset/icon_post_target_unread.svg "If x and y are integers and[m] |x| + y =0[/m], what is the value of x?"){kind=icon}
27 May 2016, 21:22
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D
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Difficulty:
55%
(hard)
Question Stats:
51% (01:28) correct
49%
(01:35)
wrong
based on 77
sessions
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Time
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If x and y are integers and\(|x| + y =0\), what is the value of x?
(1) y is non-negative integer.
(2) \(|x|*y \geq {0}\)
Self Made
(1) y is non-negative integer.
(2) \(|x|*y \geq {0}\)
Self Made
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
unverifiedvoracity
Joined: 12 Jan 2016
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Concentration: Operations, General Management
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GMAT 1: 690 Q49 V35
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WE:Supply Chain Management (Consumer Electronics)
27 May 2016, 21:42
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chetan2u
Statement 1 - y is non-negative. \(|x| \geq {0}\) and \(y \geq {0}\) . So, for \(|x| + y = 0\), both x and y have to be 0. Sufficient.
Statement 2 - \(y \geq {0}\). So, for \(|x| + y = 0\), both x and y have to be 0. Sufficient.
Hence, D.
28 May 2016, 02:53
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chetan2u
Conclusion from question statement:
|x|+y=0 with this we can figure out following two things:
#1. either both x and y are equal with opposite sign i.e. x = -y or y = -x
#2. OR both x and y equal to zero i.e. x=y=0
statement-1:
y is non-negative integer. it means either y=0 or y is +ve
from #1 and #2 and statement-1 we conclude |x|+y=0 will hold for following values of x and y:
either both x and y equal to zero i.e. x=y=0
OR y +ve and x = -y.
so we see x can take two values. hence INSUFFICIENT!
statement-2:
|x|∗y ≥ 0 - we can infer the following with this information:
A) either both x nd y equal to zero i.e. x=y=0
B) OR both x and y are +ve
C) OR both x and y are -ve
BUT 'B' and 'C' does are not in accordance with #1.
A and #2 says the same thing i.e. x=y=0
x=y=0 satisfies both |x|+y=0 AND |x|∗y ≥ 0.
hence x = 0.
Sufficient.
Answer is B.
