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gsingh0711
Joined: 02 Mar 2018
Last visit: 15 Aug 2018
Posts: 42
Given Kudos: 29
Location: India
Schools: IIMA PGPX"20 IIMA PGPX"20
GMAT 1: 640 Q51 V26
GPA: 3.1
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Updated on: 09 Aug 2018, 08:31
Originally posted by gsingh0711 on 05 Aug 2018, 09:46.
Last edited by amanvermagmat on 09 Aug 2018, 08:31, edited 2 times in total.
Last edited by amanvermagmat on 09 Aug 2018, 08:31, edited 2 times in total.
Edited the OA
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (02:39) correct
59%
(02:42)
wrong
based on 147
sessions
History
Date
Time
Result
Not Attempted Yet
What is the value of p + q + r, where p, q, r are positive integers?
(1) \(7p × 5q = 175\) and \(4p = r\)
(2) \(r\) is 200% more than \(p\) and 100% more than \(q\), where \(p + r\) is a single digit number.
(1) \(7p × 5q = 175\) and \(4p = r\)
(2) \(r\) is 200% more than \(p\) and 100% more than \(q\), where \(p + r\) is a single digit number.
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gsingh0711
Joined: 02 Mar 2018
Last visit: 15 Aug 2018
Posts: 42
Given Kudos: 29
Location: India
Schools: IIMA PGPX"20 IIMA PGPX"20
GMAT 1: 640 Q51 V26
GPA: 3.1
Products:
Updated on: 08 Aug 2018, 19:51
Originally posted by gsingh0711 on 05 Aug 2018, 09:47.
Last edited by gsingh0711 on 08 Aug 2018, 19:51, edited 1 time in total.
Last edited by gsingh0711 on 08 Aug 2018, 19:51, edited 1 time in total.
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Explanation:
Given p, q, r are positive (hence non-zero) integers. And we need to find the value of p + q + r.
Considering statement 1:
7p × 5q = 175 and 4p = r
7p × 5q = (7*1)*(5*5)
⇒ p = 1 and q = 5
and r = 4(1) = 4
⇒ p + q + r = 10
Since we are getting a definite answer from above statement, statement 1 itself is sufficient to provide the answer.
Considering statement 2:
r is 200% more than p and 100% more than q, where p + r is a single digit number
⇒ r = p + 200p/100 = 3p
and r = q + 100q/100 = 2q
⇒ p + r = p + 3p = 4p
Now, 4p is either 4 or 8
⇒ p = 1 or 2
Hence, r = 3p = 3 or 6
And r = 2q gives: q = 1.5 or 3. However, since these are positive integers, q = 3 (p cannot be 1).
⇒ p + q + r = 2 + 6 + 3 = 11
Since we are getting a definite answer from above statement, statement 2 itself is sufficient to provide the answer.
As statement 1 and 2 both alone are sufficient to provide the answer.
Answer: D.
I think, I deserve a kudus LOL
Given p, q, r are positive (hence non-zero) integers. And we need to find the value of p + q + r.
Considering statement 1:
7p × 5q = 175 and 4p = r
7p × 5q = (7*1)*(5*5)
⇒ p = 1 and q = 5
and r = 4(1) = 4
⇒ p + q + r = 10
Since we are getting a definite answer from above statement, statement 1 itself is sufficient to provide the answer.
Considering statement 2:
r is 200% more than p and 100% more than q, where p + r is a single digit number
⇒ r = p + 200p/100 = 3p
and r = q + 100q/100 = 2q
⇒ p + r = p + 3p = 4p
Now, 4p is either 4 or 8
⇒ p = 1 or 2
Hence, r = 3p = 3 or 6
And r = 2q gives: q = 1.5 or 3. However, since these are positive integers, q = 3 (p cannot be 1).
⇒ p + q + r = 2 + 6 + 3 = 11
Since we are getting a definite answer from above statement, statement 2 itself is sufficient to provide the answer.
As statement 1 and 2 both alone are sufficient to provide the answer.
Answer: D.
I think, I deserve a kudus LOL
05 Aug 2018, 10:13
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gsingh0711
You mistyped 25 as 52.
Also, I don't think Statement1 is sufficient.
7p*5q = 175
p*q = 5
p = 1 or 5
q = 5 or 1
r = 4p = 4 or 20
All of this makes Statement1 insufficient.
One way to make sure that your answer is right is to match the (p+q+r) values you get from each statement. They have to be equal.
On a side note, this question seems odd.
Statement1 says r=4p and
Statement2 says r=3p
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