HWPO
Is \(n= 2m+ 3\) ?
(1) \((n - 3)^2 = 4m^2\)
(2) \(n^2 = 4m^2 + 12m + 9\)
Bunuel , what's wrong with the following?
Is \(n= 2m+ 3\) ? => squaring both sides: is \(n^2= 4m^2+ 6m+9\) ?
Then we get a decisive answer for both statements => answer choice is D.
Whenever you raise both sides of an equation to an even power, you might get extraneous solutions. This is because raising both sides of an equation to an even power is not a reversible operation. For instance, if x = y, then x^2 = y^2. However, if x^2 = y^2, it doesn't necessarily mean x = y; it could also mean x = -y.
Take the equation x = -1 as an example. If we square both sides of the equation, we get x^2 = 1, which gives solutions x = 1 or x = -1. So, we get an extraneous solution x = 1.
Similarly, the question "Is n = 2m + 3?" cannot be directly translated to "Is n^2 = 4m^2 + 6m + 9?". This is because if from (1) n = 2m + 3, the answer is YES. However, if -n = 2m + 3, the answer is NO.
Hope it helps.