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saukrit
Joined: 05 Jul 2018
Last visit: 23 Apr 2026
Posts: 378
Given Kudos: 326
Status:Current student at IIMB
Affiliations: IIM Bangalore
Location: India
Concentration: General Management, Technology
Schools: IIMB EPGP'22 (A)
GMAT 1: 600 Q47 V26
GRE 1: Q162 V149
GPA: 3.6
WE:Information Technology (Consulting)
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14 Apr 2019, 08:29
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C
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Difficulty:
35%
(medium)
Question Stats:
71% (02:05) correct
29%
(01:59)
wrong
based on 91
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Find the area of the rectangle ABCD, if the length and breadth are odd positive integers.
(1) The perimeter of rectangle ABCD = 28 cm
(2) The area of the square whose side length is equal to the length of the rectangle, is 80% greater than the area of the rectangle.
(1) The perimeter of rectangle ABCD = 28 cm
(2) The area of the square whose side length is equal to the length of the rectangle, is 80% greater than the area of the rectangle.
Pure algebraic questions like this one are no longer part of the GMAT Data Sufficiency syllabus.
For relevant Data Sufficiency questions, please check the Data Sufficiency forum:
Data Sufficiency Forum
Data Sufficiency Forum
14 Apr 2019, 09:00
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Find the area of the rectangle ABCD, if the length and breadth are odd positive integers.
(1) The perimeter of rectangle ABCD = 28 cm
l and b can be 7 and 7 or 9 and 5 or 11 and 3 and so on
(2) The area of the square whose side length is equal to the length of the rectangle, is 80% greater than the area of the rectangle.
So \(l^2=1.8(l*b)...l=1.8b\). No values
Combined..
l is integer, so 1.8b has to be an integer, so B has to be a multiple of 5..
l can be 1.8*5=9 or 1.8*10=18..
Only 9 is possible, so l*b=5*9=45
C
(1) The perimeter of rectangle ABCD = 28 cm
l and b can be 7 and 7 or 9 and 5 or 11 and 3 and so on
(2) The area of the square whose side length is equal to the length of the rectangle, is 80% greater than the area of the rectangle.
So \(l^2=1.8(l*b)...l=1.8b\). No values
Combined..
l is integer, so 1.8b has to be an integer, so B has to be a multiple of 5..
l can be 1.8*5=9 or 1.8*10=18..
Only 9 is possible, so l*b=5*9=45
C
14 Apr 2019, 09:20
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themindful
#1
2*(l+b)=28
l+b=14
l,b= 11,3; or 13,1
insufficient
#2
area of square = l^2 = 1.8*(l*b)
or say ; l = 1.8b ; since value are integers so we can say l=2b
insufficient
from 1 & 2
3b=14
b= 14/3 ; 4.6 ~ 5
so l = 14-5 ; 9
sufficient ; IMO C l = 9 & b= 5
