In the given figure, O is the center of the circle and BC is the tangent. If AB = 10cm. What is the length of the tangent BC?
What do we have:
As a tangent is perpendicular to the circle, we know that OCB is rectangle in C.
And if we applied the theorem for rectangular triangles, we know that OB^2=OC^2+BC^2 or BC^2 = OB^2 - OC^2
OB=OA+AB and we already have AB=10cm
So what we are really looking for is the Radius of the circle, OC or OA (all 3 are equal)?
Let's start with (1) The product of the length of OB and AB is 170.
We know: OB=OA+AB and AB=10cm
OB*AB =170 = OB * 10 so OB = 17cm
OB=OA+AB or 17= OA + 10 so OA = 7cm = OC
We have everything, BC^2 = OB^2 - OC^2 = 17^2 + 7^2, no need to do the maths, only the positive value of BC is valid (lengths are positive), so (1) is sufficient and the answer is either A or D.
Let's take (2) The circumference of the circle is 14π.
Circumference of a circle is 2*pi*Radius
We have: 2*pi*R=14*pi so R=7cm = OC = OA
OB=OA+AB = 7+10=17cm
We have everything: BC^2 = OB^2 - OC^2 = 17^2 + 7^2, no need to do the maths, (2) is sufficient. So D
The correct answer is D