sjuniv32
Given \(xy ≠ 0\), is \(\frac{2}{x} > \frac{3}{y}\)?
(1) \(2y > 3x\)
(2) \(xy > 0\)
Question: is \(\frac{2}{x} > \frac{3}{y}\)?Statement 1: \(2y > 3x\)for x. and y both positive, the answer to the question will be yes but
for x negative and y positive, the answer to the question will be no hence
NOT SUFFICIENTStatement 2: \(xy > 0\)their absolute values are incomparable hence we can not compare 2/x with 3/y hence
NOT SUFFICIENTCOmbining\(xy > 0\) and \(2y > 3x\)
dividing by xy both sides we get
\(\frac{2}{x} > \frac{3}{y}\)
SUFFICIENTAnswer: Option C
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