Quote:
Water can be pumped from a 100,000 gallon tank at a uniform rate by opening valve V, valve W, or both. The rate at which water is pumped out by opening valve V is 10,000 gallons per hour. If the tank is completely full and both valves are opened, the tank can be drained in 6 hours. How long would it take to empty the tank if it were 80% full and only valve W were opened?
Step 1: Understanding the questionVolume of tank = 100,000 gallon
Let rate of value V be v and rate of valve W be w
v = 10,000 gallons per hour
Step 2: CalculationWhen tank is full, Work = 100,000 gallon, Time to drain = 6 hours, Combined rate = (v+w) = (10000+w)
Using Rate * Time = Work equation
(10,000+w) * 6 = 100,000
w = (100,00/6) - 10,000 = 40,000/6 = 20,000/3
When tank is 80% full, Work = 80,000 gallon, Time to drain = t hours, Combined rate = w = 20,000/3
Using Rate * Time = Work equation
20,000/3 * t = 80,000
t = 12hours
C is correct
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