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27 Oct 2018, 10:29
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A cube with its sides numbered 1— 6 is rolled twice, first landing on a and then landing on b. If any roll of the cube yields an equal chance of landing on any of the numbers 1 — 6, what is the probability that a + b is prime?
A) 0
B) \(\frac{1}{12}\)
C) \(\frac{5}{12}\)
D) \(\frac{7}{18}\)
E) \(\frac{4}{9}\)
A) 0
B) \(\frac{1}{12}\)
C) \(\frac{5}{12}\)
D) \(\frac{7}{18}\)
E) \(\frac{4}{9}\)
Weekly Quant Quiz #6 Question No 10
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27 Oct 2018, 13:21
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Prime nos between 1-12 : 2 , 3 , 5 , 7, 11
for 2 : (1,1) : 1/6*1/6 = 1/36
3 : (2,1), (1,2): 2 * 1/6 * 1/6 = 1/18
5 : (1,4) and (2,3) = 4*1/6*1/6 = 2/18
7 : (1,6) , (2,5) , (3,4) = 6*1/6*1/6 = 3/18
11 : (6,5) = 2*1/6*1/6 = 1/18
Total = 15/36 = 5/12
for 2 : (1,1) : 1/6*1/6 = 1/36
3 : (2,1), (1,2): 2 * 1/6 * 1/6 = 1/18
5 : (1,4) and (2,3) = 4*1/6*1/6 = 2/18
7 : (1,6) , (2,5) , (3,4) = 6*1/6*1/6 = 3/18
11 : (6,5) = 2*1/6*1/6 = 1/18
Total = 15/36 = 5/12
28 Oct 2018, 01:12
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total outcome 36
prime comb 15
2,3,5,7
3,5,7
5,7
5,7
7,11
7,11
hence -> 15/36 --> 5/12 (C)
prime comb 15
2,3,5,7
3,5,7
5,7
5,7
7,11
7,11
hence -> 15/36 --> 5/12 (C)
