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26 Sep 2004, 23:14
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What are the areas of the two triangles formed by extending the legs of a trapezoid until they intersect?
1. Area of trapezoid = 100, bases 6 and 14.
2. Height of trapezoid = 10.
1. Area of trapezoid = 100, bases 6 and 14.
2. Height of trapezoid = 10.
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27 Sep 2004, 00:48
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E.
1. Insuff. Area of trapezium = 1/(sum of parallel sides) x height. =>100=1/2(6+14)xh. =>h=10. Not enough info to determine the area of two triangles.
2. Insuff. Gives the same info as above.
Together, still insufficient. Hence E.
1. Insuff. Area of trapezium = 1/(sum of parallel sides) x height. =>100=1/2(6+14)xh. =>h=10. Not enough info to determine the area of two triangles.
2. Insuff. Gives the same info as above.
Together, still insufficient. Hence E.
27 Sep 2004, 02:17
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If i got the picture right : A.
T = area of trapezoid.
x = small base
y = large base
H= Height of Big triangle
h= Height of Small triangle
We know that T + x*h/2 = y*H/2
Statement A: T=100, x=6, y=14.
So
100 + 6*h/2 = 14*H/2.
We also know that 100=(x+y)*(H-h).
100=20(H-h)
H=5+h.
With those Two equations we will find h and H, which were missing to answer the question.
T = area of trapezoid.
x = small base
y = large base
H= Height of Big triangle
h= Height of Small triangle
We know that T + x*h/2 = y*H/2
Statement A: T=100, x=6, y=14.
So
100 + 6*h/2 = 14*H/2.
We also know that 100=(x+y)*(H-h).
100=20(H-h)
H=5+h.
With those Two equations we will find h and H, which were missing to answer the question.
