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05 May 2020, 04:03
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Difficulty:
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Question Stats:
76% (02:30) correct
24%
(02:29)
wrong
based on 228
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What is the area enclosed of the region enclosed by y = |x – 1| + 2, x = 1, x–axis and y–axis?
A. 2.5
B. 5
C. 7
D. 9
E. 10
Are You Up For the Challenge: 700 Level Questions
A. 2.5
B. 5
C. 7
D. 9
E. 10
Are You Up For the Challenge: 700 Level Questions
03 Jun 2020, 02:07
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Area \(= (2*1)+\frac{1}{2} *1*1 = 2.5\)
Bunuel
General Discussion
05 May 2020, 08:39
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What is the area enclosed of the region enclosed by y = |x – 1| + 2, x = 1, x–axis and y–axis?
A. 2.5 --> correct: y = |x – 1| + 2, so (1) x=1, y=2 & if you increase or decrease x, y will always increase linearly with slop of 1, and intersect y-axis (2) @x=0, y=3, so enclosure enclosed by x = 1, x–axis and y–axis looks like trapezium with height=1, and two unequal side length = 2&3, so the area= (1/2)*(2+3)*1=5/2=2.5
B. 5
C. 7
D. 9
E. 10
A. 2.5 --> correct: y = |x – 1| + 2, so (1) x=1, y=2 & if you increase or decrease x, y will always increase linearly with slop of 1, and intersect y-axis (2) @x=0, y=3, so enclosure enclosed by x = 1, x–axis and y–axis looks like trapezium with height=1, and two unequal side length = 2&3, so the area= (1/2)*(2+3)*1=5/2=2.5
B. 5
C. 7
D. 9
E. 10
