GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Feb 2019, 13:05

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in February
PrevNext
SuMoTuWeThFrSa
272829303112
3456789
10111213141516
17181920212223
242526272812
Open Detailed Calendar
  • Free GMAT Algebra Webinar

     February 17, 2019

     February 17, 2019

     07:00 AM PST

     09:00 AM PST

    Attend this Free Algebra Webinar and learn how to master Inequalities and Absolute Value problems on GMAT.
  • Valentine's day SALE is on! 25% off.

     February 18, 2019

     February 18, 2019

     10:00 PM PST

     11:00 PM PST

    We don’t care what your relationship status this year - we love you just the way you are. AND we want you to crush the GMAT!

What is the area of the above right triangle, in terms of x?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 52906
What is the area of the above right triangle, in terms of x?  [#permalink]

Show Tags

New post 09 Sep 2018, 08:03
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

85% (01:06) correct 15% (01:26) wrong based on 51 sessions

HideShow timer Statistics

Image
What is the area of the above right triangle, in terms of x?


A. x^2/8

B. x^2/4

C. \(\frac{x^2\sqrt{2}}{2}\)

D. \(x^2\sqrt{2}\)

E. \(\frac{x^2\sqrt{2}}{4}\)


Attachment:
image015.jpg
image015.jpg [ 1.5 KiB | Viewed 660 times ]

_________________

New to the Math Forum?
Please read this: Ultimate GMAT Quantitative Megathread | All You Need for Quant | PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

Resources:
GMAT Math Book | Triangles | Polygons | Coordinate Geometry | Factorials | Circles | Number Theory | Remainders; 8. Overlapping Sets | PDF of Math Book; 10. Remainders | GMAT Prep Software Analysis | SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) | Tricky questions from previous years.

Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
Extra-hard Quant Tests with Brilliant Analytics

Director
Director
User avatar
G
Joined: 20 Feb 2015
Posts: 795
Concentration: Strategy, General Management
Premium Member
What is the area of the above right triangle, in terms of x?  [#permalink]

Show Tags

New post 09 Sep 2018, 08:19
Bunuel wrote:
Image
What is the area of the above right triangle, in terms of x?


A. x^2/8

B. x^2/4

C. \(\frac{x^2\sqrt{2}}{2}\)

D. \(x^2\sqrt{2}\)

E. \(\frac{x^2\sqrt{2}}{4}\)

Attachment:
image015.jpg


The measure of the angles of the given triangle is surely 45:45:90
the ratio of sides of such triangle is 1:1:\(\sqrt{2}\)

now it is given that
\(\sqrt{2}\)*p = x (where p is the measure of each side)
p = x/\(\sqrt{2}\)

area =\(\frac{b*h}{2}\) = x/\(\sqrt{2}\)* x/\(\sqrt{2}\) * 1/2 = \(x^2\)/4
Intern
Intern
avatar
B
Joined: 28 Feb 2018
Posts: 1
Re: What is the area of the above right triangle, in terms of x?  [#permalink]

Show Tags

New post 09 Sep 2018, 08:53
as both sides of right angle triangle are equal
2*side^2=x^2
side^2=x^2/2

area of triangle=(1/2)*(side^2)
=(1/2)*((x^2)/2)=(1/4)*(x^2)
Intern
Intern
avatar
B
Joined: 24 Dec 2011
Posts: 28
Location: India
GPA: 4
WE: General Management (Health Care)
Re: What is the area of the above right triangle, in terms of x?  [#permalink]

Show Tags

New post 09 Sep 2018, 18:02
Angle 45 indicates that it is a isosceles right angle triangle in which the sides are in the ratio 1:1:√2
√2a= x
a= x/√2
area= 1/2bh
½ *(x/√2)* (x/√2)
Comes to x2/4
Board of Directors
User avatar
P
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4383
Location: India
GPA: 3.5
WE: Business Development (Commercial Banking)
GMAT ToolKit User Premium Member CAT Tests
Re: What is the area of the above right triangle, in terms of x?  [#permalink]

Show Tags

New post 10 Sep 2018, 06:50
Bunuel wrote:
Image
What is the area of the above right triangle, in terms of x?


A. x^2/8

B. x^2/4

C. \(\frac{x^2\sqrt{2}}{2}\)

D. \(x^2\sqrt{2}\)

E. \(\frac{x^2\sqrt{2}}{4}\)


Attachment:
image015.jpg


The given triangle is an isosceles right-angled triangle...

So, \(a^2 + a^2 = x^2\)

Or, \(2a^2 = x^2\)

Or, \(a^2 = \frac{x^2}{2}\)

Since area of a triangle is \(\frac{1}{2}*base*Altitude\) = \(\frac{x^2}{4}\), Answer must be (B)
_________________

Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )

GMAT Club Bot
Re: What is the area of the above right triangle, in terms of x?   [#permalink] 10 Sep 2018, 06:50
Display posts from previous: Sort by

What is the area of the above right triangle, in terms of x?

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.