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Updated on: 01 May 2013, 05:36
Originally posted by mathewmithun on 01 May 2013, 05:32.
Last edited by Bunuel on 01 May 2013, 05:36, edited 1 time in total.
Last edited by Bunuel on 01 May 2013, 05:36, edited 1 time in total.
Edited the question.
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
80% (01:01) correct
20%
(01:22)
wrong
based on 86
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
Untitled.png
What is the area of the circle above with center O?(1) The length of major arc CA is 27pi
(2) The perimeter of OABC is 72
I choose A, but the OA is D. Please help me understand the solution.
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aceacharya
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01 May 2013, 05:40
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The Quadrilateral OABC is evidently a square as
1. OA = OC
2. /_AOC is 90deg.
3. /_OAB is 90deg. as tangent is perpendicular to radius (as percieved from figure)
So statement A gives the value of pi*(360-90)/360*r, from which r can be calculated
Statement B gives the perimieter of the square which is 4r so r can be calculated
Both are independently sufficient
1. OA = OC
2. /_AOC is 90deg.
3. /_OAB is 90deg. as tangent is perpendicular to radius (as percieved from figure)
So statement A gives the value of pi*(360-90)/360*r, from which r can be calculated
Statement B gives the perimieter of the square which is 4r so r can be calculated
Both are independently sufficient
01 May 2013, 07:21
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aceacharya
You have assumed that quadrilateral is a square. My question and doubt is precisely that, to which level we can assume things from the figure? It is not mentioned in question that AB and CB is tangent to the circle.
