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Bunuel

What is the area of the shaded region in the figure above?

(A) 72
(B) 57
(C) 55
(D) 54 1/2
(E) 49 1/2

Attachment:
2017-12-18_1010.png

Area of the shaded region in the figure= Area of the region(Rectangle) - Area of unshaded region(trapezium)

Area of rectangle = 8*9 =72

Area of trapezium = (a+b/2)*h = (10/2)*3 = 15

72-15= 57

Hence B

*Corrected Typo*
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Bunuel

What is the area of the shaded region in the figure above?

(A) 72
(B) 57
(C) 55
(D) 54 1/2
(E) 49 1/2

Attachment:
2017-12-18_1010.png

Note that the slanting line has end points at (4, 6) and (6, 9).
Area of the trapezium so formed = (1/2)*3*(4 + 2) = 9

Area of the rest of the shaded rectangle = 6*8 = 48

Total shaded area = 9 + 48 = 57

Answer (B)
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Bunuel

What is the area of the shaded region in the figure above ?

(A) 72
(B) 57
(C) 55
(D) 54 1/2
(E) 49 1/2

Attachment:
Untitled.png


Here's another way to do this problem:

Area of shaded region = Area of square - area of unshaded region (trapezoid, in this case)

Area of square = B*H --> 8*9 = 72

Area of unshaded region = (B1+B2)/2 *H --> (6+4)/2 * 3 =15

Area of shaded region = 72-15 = 57
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  • Observe that -> Area of the shaded region = Area of the big rectangle (created by the x axis, the y axis, x = 9, and y = 8) - Area of the unshaded trapezium
  • Area of the big rectangle = 9 x 8 = 72
  • Area of the trapezium = \(\frac{1}{2}\) x (sum of parallel sides) x (distance between parallel sides) = \(\frac{1}{2}\) x (6+4) x (3) = 15
  • So, area of the shaded region = 72 - 15 = 57. Choice B.

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Harsha
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