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# What is the area of the triangle shown above?

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Math Expert
Joined: 02 Sep 2009
Posts: 51098
What is the area of the triangle shown above?  [#permalink]

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23 Aug 2018, 02:41
00:00

Difficulty:

15% (low)

Question Stats:

86% (00:42) correct 14% (00:49) wrong based on 22 sessions

### HideShow timer Statistics

What is the area of the triangle shown above?

A. $$\frac{25\sqrt{2}}{3}$$

B. $$\frac{25\sqrt{3}}{2}$$

C. 25

D. $$25\sqrt{2}$$

E. $$25\sqrt{3}$$

Attachment:

image007.jpg [ 2.53 KiB | Viewed 264 times ]

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What is the area of the triangle shown above?  [#permalink]

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23 Aug 2018, 02:50
Bunuel wrote:

What is the area of the triangle shown above?

A. $$\frac{25\sqrt{2}}{3}$$

B. $$\frac{25\sqrt{3}}{2}$$

C. 25

D. $$25\sqrt{2}$$

E. $$25\sqrt{3}$$

Attachment:
image007.jpg

The given triangle is a 30-60-90 triangle.

So, the sides are in the ratio $$x:\sqrt{3}x:2x$$
Given, 2x=10 or, x=5

So, base=x=5, $$height=\sqrt{3}x=5\sqrt{3}$$
So, $$Area=1/2*base*height=1/2*5*5\sqrt{3}=\frac{25\sqrt{3}}{2}$$

Ans. (B)
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What is the area of the triangle shown above? &nbs [#permalink] 23 Aug 2018, 02:50
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