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17 Jan 2014, 05:57
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
80% (02:03) correct
20%
(02:14)
wrong
based on 422
sessions
History
Date
Time
Result
Not Attempted Yet
Attachment:
pic.jpg [ 14.13 KiB | Viewed 10372 times ]
A) 10
B) 15
C) 20
D) 25
E) 30
17 Jan 2014, 05:58
Kudos
Bookmarks
What would be the quickest way of solving this? I created two additional right triangles as shown.
pic2.jpg [ 18.86 KiB | Viewed 10232 times ]
Based on the drawing I made blow, the red (3-4-5) and green (6-8-10) are both derivatives of 3-4-5 triangles.
Thus, you get the hypotenuses, can multiple them together and then by 1/2 to get the triangle area formula of 1/2 * base * height.
This yields 25. Answer D.
When I read the OA, however, I didn’t understand this necessarily: It was written that before even calculating the area, one must test if the original triangle is a right triangle. They did that somehow with the slope (appreciate ideas/answers), which I didn’t understand.
I just assumed it looks like a right triangle, but surely it is not explicitly stated nor is there a small square in the corner to indicate it is (as I indicated for the red and green triangle).
Thanks.
Attachment:
pic2.jpg [ 18.86 KiB | Viewed 10232 times ]
Based on the drawing I made blow, the red (3-4-5) and green (6-8-10) are both derivatives of 3-4-5 triangles.
Thus, you get the hypotenuses, can multiple them together and then by 1/2 to get the triangle area formula of 1/2 * base * height.
This yields 25. Answer D.
When I read the OA, however, I didn’t understand this necessarily: It was written that before even calculating the area, one must test if the original triangle is a right triangle. They did that somehow with the slope (appreciate ideas/answers), which I didn’t understand.
I just assumed it looks like a right triangle, but surely it is not explicitly stated nor is there a small square in the corner to indicate it is (as I indicated for the red and green triangle).
Thanks.
17 Jan 2014, 09:22
Kudos
Bookmarks
BabySmurf
The area of the triangle when the vertices are specified is given by (In determinant form):
If the points are provided as (x1, y1), (x2,y2) and (x3,y3) -> the formula is attached along with the post.
If you expand the determinant
1/2 [ x1 (y2 * 1 - y3*1) - y1 (x2 * 1 - x3*1) + 1 (x2*y3 - x3 * y2)] and take the +ve value of it. (The value might come in -ve, but ignore that and take Modulus (||) of the value)
P.S. I have never seen this kind of question in GMAT, but this appeared in previous CAT
Attachments
File comment: Formula
Formula.png [ 2.34 KiB | Viewed 9989 times ]
