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Bunuel
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Bunuel
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14


Avg=(a+b+c)/3

From Equation A, we neither find value of individual variable(a,b,c) nor we can find the sum (a+b+b+c)

From Equation B also we can not find value of individual variable(a,b,c) or the sum (a+b+b+c)

Using both equation:-
4(a+b+c)=10;
=> (a+b+c)=10/4

so the avg will be 10/12
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Hi PKGMAT,
4(a+b+c)=10+14=24.

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Bunuel
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

(1) a + 2b + 3c = 10

Insufficient

(2) 3a + 2b + c = 14

Insufficient

Combining (1) & (2),

Adding both equations,
—> 4a + 4b + 4c = 24
—> a + b + c = 6

Average = 6/3 = 2

Sufficient

Option C

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What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

Statement 1:
Diving by 3: (a+2b)/3 + c = 3.33

Statement 2:
Diving by 3: (c+2b)/3 + a = 4.66

Now adding: 4a + 4b + 4c = 24. thus a+b+c = 6

Thus C
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