Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 16 Jul 2019, 13:37 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # What is the average (arithmetic mean) of a, b, and c ?

Author Message
TAGS:

### Hide Tags

Math Expert V
Joined: 02 Sep 2009
Posts: 56244
What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags 00:00

Difficulty:   25% (medium)

Question Stats: 74% (00:59) correct 26% (01:36) wrong based on 80 sessions

### HideShow timer Statistics What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

_________________
Retired Moderator D
Joined: 25 Feb 2013
Posts: 1197
Location: India
GPA: 3.82
What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags

1
2
Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

Basically we need the value of $$a+b+c$$, to determine the average

Statement 1: $$a+2b+3c=10$$ cannot be factorized to get $$a+b+c$$. Insufficient

Statement 2: $$3a+2b+c=14$$ cannot be factorized to get $$a+b+c$$. Insufficient

Combining 1 & 2: add the two equations to get $$4a+4b+4c=24 => a+b+c=6$$. Sufficient

Option C
VP  D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 1028
WE: Supply Chain Management (Energy and Utilities)
Re: What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags

Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

Combining (1) (2), we have
a + 2b + 3c +3a + 2b + c =4(a+b+c)=24
Now, AM(a,b,c)=$$\frac{(a+b+c)}{3}$$=$$\frac{24}{4*3}$$
So, AM of a,b, and c is 2.
Sufficient.

Ans. (C)
_________________
Regards,

PKN

Rise above the storm, you will find the sunshine
Intern  B
Joined: 01 Jul 2018
Posts: 6
Location: India
Concentration: Finance, General Management
WE: Science (Education)
Re: What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags

Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

Avg=(a+b+c)/3

From Equation A, we neither find value of individual variable(a,b,c) nor we can find the sum (a+b+b+c)

From Equation B also we can not find value of individual variable(a,b,c) or the sum (a+b+b+c)

Using both equation:-
4(a+b+c)=10;
=> (a+b+c)=10/4

so the avg will be 10/12
VP  D
Status: Learning stage
Joined: 01 Oct 2017
Posts: 1028
WE: Supply Chain Management (Energy and Utilities)
Re: What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags

Hi PKGMAT,
4(a+b+c)=10+14=24.

Posted from my mobile device
_________________
Regards,

PKN

Rise above the storm, you will find the sunshine
Director  G
Joined: 20 Jul 2017
Posts: 526
Location: India
Concentration: Entrepreneurship, Marketing
WE: Education (Education)
Re: What is the average (arithmetic mean) of a, b, and c ?  [#permalink]

### Show Tags

Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14

(1) a + 2b + 3c = 10

Insufficient

(2) 3a + 2b + c = 14

Insufficient

Combining (1) & (2),

—> 4a + 4b + 4c = 24
—> a + b + c = 6

Average = 6/3 = 2

Sufficient

Option C

Posted from my mobile device Re: What is the average (arithmetic mean) of a, b, and c ?   [#permalink] 13 Jul 2019, 13:03
Display posts from previous: Sort by

# What is the average (arithmetic mean) of a, b, and c ?  