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What is the average (arithmetic mean) of a, b, and c ?

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Bunuel
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What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  10 Jul 2018, 21:29
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What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14
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niks18
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What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  10 Jul 2018, 21:40
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Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14


Basically we need the value of \(a+b+c\), to determine the average

Statement 1: \(a+2b+3c=10\) cannot be factorized to get \(a+b+c\). Insufficient

Statement 2: \(3a+2b+c=14\) cannot be factorized to get \(a+b+c\). Insufficient

Combining 1 & 2: add the two equations to get \(4a+4b+4c=24 => a+b+c=6\). Sufficient

Option C
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PKN
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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  10 Jul 2018, 22:12
Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14


Combining (1) (2), we have
a + 2b + 3c +3a + 2b + c =4(a+b+c)=24
Now, AM(a,b,c)=\(\frac{(a+b+c)}{3}\)=\(\frac{24}{4*3}\)
So, AM of a,b, and c is 2.
Sufficient.

Ans. (C)
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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  12 Jul 2018, 10:48
Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14



Avg=(a+b+c)/3

From Equation A, we neither find value of individual variable(a,b,c) nor we can find the sum (a+b+b+c)

From Equation B also we can not find value of individual variable(a,b,c) or the sum (a+b+b+c)

Using both equation:-
4(a+b+c)=10;
=> (a+b+c)=10/4

so the avg will be 10/12
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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  12 Jul 2018, 10:52
Hi PKGMAT,
4(a+b+c)=10+14=24.

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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  13 Jul 2019, 13:03
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Bunuel wrote:
What is the average (arithmetic mean) of a, b, and c ?

(1) a + 2b + 3c = 10

(2) 3a + 2b + c = 14


(1) a + 2b + 3c = 10

Insufficient

(2) 3a + 2b + c = 14

Insufficient

Combining (1) & (2),

Adding both equations,
—> 4a + 4b + 4c = 24
—> a + b + c = 6

Average = 6/3 = 2

Sufficient

Option C

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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink] New post  07 Mar 2023, 11:45
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Re: What is the average (arithmetic mean) of a, b, and c ? [#permalink]
07 Mar 2023, 11:45
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