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10 Jul 2018, 21:29
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
75% (00:57) correct
25%
(01:34)
wrong
based on 779
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What is the average (arithmetic mean) of a, b, and c ?
(1) a + 2b + 3c = 10
(2) 3a + 2b + c = 14
(1) a + 2b + 3c = 10
(2) 3a + 2b + c = 14
10 Jul 2018, 21:40
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Bunuel
Basically we need the value of \(a+b+c\), to determine the average
Statement 1: \(a+2b+3c=10\) cannot be factorized to get \(a+b+c\). Insufficient
Statement 2: \(3a+2b+c=14\) cannot be factorized to get \(a+b+c\). Insufficient
Combining 1 & 2: add the two equations to get \(4a+4b+4c=24 => a+b+c=6\). Sufficient
Option C
General Discussion
10 Jul 2018, 22:12
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Bunuel
Combining (1) (2), we have
a + 2b + 3c +3a + 2b + c =4(a+b+c)=24
Now, AM(a,b,c)=\(\frac{(a+b+c)}{3}\)=\(\frac{24}{4*3}\)
So, AM of a,b, and c is 2.
Sufficient.
Ans. (C)
