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30 Oct 2019, 23:31
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
57% (00:48) correct
43%
(01:16)
wrong
based on 47
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What is the cost, in cents, of using a certain fax machine to send n pages of a report if the total cost for sending the first k pagers is r cents and the cost for sending each additional page is s cents? (Assume that n > k.)
(A) \(r + s (n - k)\)
(B) \(r + s (n + k)\)
(C) \(rs(n + k)\)
(D) \(kr + s(n - k)\)
(E) \(kr + ns\)
(A) \(r + s (n - k)\)
(B) \(r + s (n + k)\)
(C) \(rs(n + k)\)
(D) \(kr + s(n - k)\)
(E) \(kr + ns\)
31 Oct 2019, 01:12
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What is the cost, in cents, of using a certain fax machine to send n pages of a report if the total cost for sending the first k pagers is r cents and the cost for sending each additional page is s cents? (Assume that n > k.)
Cost of initial k pages = r cents
Cost of s pages thereafter = (n-k)s
Total =\(r+s(n-k)\).......
A
Let n=100, k =10 and r=50 and s=1..
10 pages cost = 50
90 after that cost = 90*1=90
Total=50+90=140
Check choices
(A) \(r + s (n - k)......50+(100-10)=140\)..YES
(B) \(r + s (n + k)......50+(100+10)=160\)
(C) \(rs(n + k)......50(100+10)=5500\)
(D) \(kr + s(n - k)....10*50+90=590\)
(E) \(kr + ns....500+100=600\)
A
Algebraic way
Cost of initial k pages = r cents
Cost of s pages thereafter = (n-k)s
Total =\(r+s(n-k)\).......
A
Another way would be to take values....
Let n=100, k =10 and r=50 and s=1..
10 pages cost = 50
90 after that cost = 90*1=90
Total=50+90=140
Check choices
(A) \(r + s (n - k)......50+(100-10)=140\)..YES
(B) \(r + s (n + k)......50+(100+10)=160\)
(C) \(rs(n + k)......50(100+10)=5500\)
(D) \(kr + s(n - k)....10*50+90=590\)
(E) \(kr + ns....500+100=600\)
A
31 Oct 2019, 06:25
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Solution
Given
- • The total cost for sending the first k pages using a certain fax machine = r cents
• The cost for sending the each additional page using the same machine = s cents
• n > k
To find
- • The cost in cents, of using a certain fax machine to send n pages of a report.
Approach and Working out
- • n pages= First k pages + (n-k) pages
• Cost to send n pages = Cost to send first k pages + Cost to send (n-k) pages
• = r + (n-k)s
Thus, option A is the correct answer.
Correct Answer: Option A
