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\(=2^{10}(5^4 -5^2*2^3+2*4)\\
\)
\(= 2^{10}(625-200+16)\)
\(= 2^{10}(441)\)
\(= 2^{10}* 7*7*9\)
thus greatest prime divisor is 7
C
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Rdbasak
What is the greatest prime factor of \(2^{10}*5^4-2^{13}*5^2+2^{14}\)?


    A. 2
    B. 3
    C. 7
    D. 11
    E. 13

Hello!
I found an alternate quick method which can be done using the units digit of the numbers.
Units digit of each number shall be:-
2^10*5^4 - 2^13*5^2 + 2^14= 4 x 5 - 2 x 5 + 4
It adds upto 14.

7 is the closest answer which i found!

OA-: Option C

Let me know if it does not suffice!

Thank you!
Cheers :thumbsup:

Regards,
Raunak Damle
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Rdbasak
What is the greatest prime factor of \(2^{10}*5^4-2^{13}*5^2+2^{14}\)?


    A. 2
    B. 3
    C. 7
    D. 11
    E. 13

Factoring, we have:

2^10(5^4 - 2^3 * 5^2 + 2^4)

2^10(625 - 200 + 16)

2^10(441)

2^10(9 x 49)

2^10 x 3^2 x 7^2

Thus, the largest prime factor is 7.

Answer: C
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Rdbasak
What is the greatest prime factor of \(2^{10}*5^4-2^{13}*5^2+2^{14}\)?


    A. 2
    B. 3
    C. 7
    D. 11
    E. 13

Asked: What is the greatest prime factor of \(2^{10}*5^4-2^{13}*5^2+2^{14}\)?

\(2^{10}*5^4-2^{13}*5^2+2^{14}\)
\(= 2^{10}(5^4 - 2^3*5^2 + 2^4)\)
\(= 2^{10}(625 - 200 + 16) \)
\(= 2^{10}(441)\)
\(= 2^{10}*3^2*7^2\)

IMO C

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