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Re: What is the LCM of n C1 and n C2, where n is odd? [#permalink]
Answer should be B substitute 3 5 and 7 to find out.
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Re: What is the LCM of n C1 and n C2, where n is odd? [#permalink]
nC1=n!/(n-1)!=n
nC2=n!/(2*(n-2)!)=n*(n-1)/2

(A): n/nC1= n/n=1 OK
n/nC2=2(n-1), and since n is odd integer greater than 2, n>3. 2/(3-1)=1, 2/(5-1)=1/2 NOT OK.

(B) n(n-1)/2/nC1=(n-1)/2 OK
n(n-1)/2/nC2=1 OK

(C) doesn't work

(D) doesn't work

(E) doesn't work
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Re: What is the LCM of n C1 and n C2, where n is odd? [#permalink]
nC1= n and nC2=n(n - 1)/2
We see that nC2 is a multiple of nC1.
The LCM of two numbers where one is the multiple of the other, is the larger number.
For eg: The LCM of 12 and 48 is 48.
We know that (n - 1)/2 is greater than 1 as n is greater than 2. Therefore, n(n - 1)/2 is greater than n and hence the answer.
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Re: What is the LCM of n C1 and n C2, where n is odd? [#permalink]
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Re: What is the LCM of n C1 and n C2, where n is odd? [#permalink]
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