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15 Jun 2021, 06:00
Kudos
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
59% (01:36) correct
41%
(01:32)
wrong
based on 271
sessions
History
Date
Time
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Not Attempted Yet
What is the LCM of nC1 and nC2, where n is an odd integer greater than 2?
(A) n
(B) n(n - 1)/2
(C) (n - 1)/2
(D) n/2
(E) n − 1
(A) n
(B) n(n - 1)/2
(C) (n - 1)/2
(D) n/2
(E) n − 1
15 Jun 2021, 06:20
Kudos
Bookmarks
Answer: A
Any odd number greater than 2 would work.
Let n=3
3C1 = 3!/(2!*1!)
= 3
3C2 = 3!(2!*1!)
= 3
Since n =3, then the LCM of nC1 and nC2 = n
Posted from my mobile device
Any odd number greater than 2 would work.
Let n=3
3C1 = 3!/(2!*1!)
= 3
3C2 = 3!(2!*1!)
= 3
Since n =3, then the LCM of nC1 and nC2 = n
Posted from my mobile device
15 Jun 2021, 09:29
Kudos
Bookmarks
abuc0112
Answer: A
Any odd number greater than 2 would work.
Let n=3
3C1 = 3!/(2!*1!)
= 3
3C2 = 3!(2!*1!)
= 3
Since n =3, then the LCM of nC1 and nC2 = n
Posted from my mobile device
Any odd number greater than 2 would work.
Let n=3
3C1 = 3!/(2!*1!)
= 3
3C2 = 3!(2!*1!)
= 3
Since n =3, then the LCM of nC1 and nC2 = n
Posted from my mobile device
Can you please check with other odd numbers such as 5 or 7, you may not find that LCM is 5 or 7.
It seems LCM will be nC2, option B, I may be wrong but n doesn’t seem to be the right answer.
