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02 Oct 2017, 11:22
Kudos
Bookmarks
D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
94% (00:42) correct
6%
(00:26)
wrong
based on 43
sessions
History
Date
Time
Result
Not Attempted Yet
What is the least number of squares with area 9 to cover completely, without overlap, a square with side of length 9?
(A) 2
(B) 3
(C) 4
(D) 9
(E) 12
(A) 2
(B) 3
(C) 4
(D) 9
(E) 12
02 Oct 2017, 13:09
Kudos
Bookmarks
Bunuel
Area:
The big square has area (9*9) = 81
The small squares have area 9
Larger area/ smaller areas = number of squares with the smaller area
81 / 9 = Answer D
Side length:
Small squares' area = 9. Their sides have a length of 3.
How many short lengths will fit into a longer length?
9 / 3 = 3 small side lengths fit without overlap into one side length
But they're two-dimensional squares. Area = Length times length. We have one length calculated. We need two. We have to consider a second side of the big square.
A second side: 9 / 3 = 3
Now multiply:
(# of small that fit on one side) * (# that fit on another side): 3 * 3 = 9
Answer D
02 Oct 2017, 23:43
Kudos
Bookmarks
Bunuel
Area to be covered = Area of square with side 9 = 9^2 = 81
Area of squares to be used cover the bigger square = 9
Number of Smaller squares = Area of bigger square / Area of small square = 81/9 = 9
Answer: Option D
