Markella24 wrote:
We notice here that all 44, 56 and 32 are multiples of 4. So, to help our calculations we can rephrase as follows:
What is the least number that when divided by 11 leaves a remainder 9, when divided by 14 leaves a remainder 11, and when divided by 8 leaves a remainder 3? (notice here that I calculated new remainders based on the new divisors so e.g. 11 divides 31 and leaves a remainder of 9).
Next, I am attacking the answer choices starting from choice C (middle value). In this case, it does not really matter where you start but it is usually helpful to start in the middle.
I choose to test with 11.
So, I take my answer choice and substract the remainder i.e. 2451-9=2442
According to the divisibility rules if a number is a multiple of 11 then by substracting the value of the last digit from the rest of the number you should get a multiple of 11 and this is a repeatable process.
Therefore,
244-2=242, which is a multiple of 11! However, if you were not able to identify that, you could repeat the process and get:
24-2=22, here you should easily identify that this is a multiple of 11. And there you have your answer C.
Shouldn't the remainder be 1 when the number is divided by14? 43 = 14*3 + 1.
or am i missing something here?
and good take on divisibility by 11. This method seems simpler than the difference of odd and even values rule, provided i can remember it