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What is the length of hypotenuse k?

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What is the length of hypotenuse k?  [#permalink]

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New post 04 Nov 2019, 03:54
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Re: What is the length of hypotenuse k?  [#permalink]

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New post 04 Nov 2019, 05:02
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AE= \(\sqrt{13^2-12^2}\)=5

BE=12.2 - 5=7.2


Triangle AEC is similar to Triangle BDE

Hence, \(\frac{EC}{CA}=\frac{DE}{BE}\)

\(\frac{13}{12}=\frac{DE}{7.2}\)

DE=7.8


Bunuel wrote:
Image
What is the length of hypotenuse k?

(A) 9
(B) 7.8
(C) 7
(D) 6.9
(E) 6.8


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Re: What is the length of hypotenuse k?  [#permalink]

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New post 05 Nov 2019, 21:41
nick1816 wrote:
AE= \(\sqrt{13^2-12^2}\)=5

BE=12.2 - 5=7.2


Triangle AEC is similar to Triangle BDE

Hence, \(\frac{EC}{CA}=\frac{DE}{BE}\)

\(\frac{13}{12}=\frac{DE}{7.2}\)

DE=7.8


Bunuel wrote:
Image
What is the length of hypotenuse k?

(A) 9
(B) 7.8
(C) 7
(D) 6.9
(E) 6.8


Are You Up For the Challenge: 700 Level Questions


Attachment:
1b.jpg

EC/CA=ED/DB , what you have done with the similarity property is wrong

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What is the length of hypotenuse k?  [#permalink]

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New post Updated on: 06 Nov 2019, 01:34
In Triangle AEC

Cosecant(x)= EC/CA

In Triangle BDE

Cosecant(x)= DE/BE




Peddi wrote:
nick1816 wrote:
AE= \(\sqrt{13^2-12^2}\)=5

BE=12.2 - 5=7.2


Triangle AEC is similar to Triangle BDE

Hence, \(\frac{EC}{CA}=\frac{DE}{BE}\)

\(\frac{13}{12}=\frac{DE}{7.2}\)

DE=7.8


Bunuel wrote:
Image
What is the length of hypotenuse k?

(A) 9
(B) 7.8
(C) 7
(D) 6.9
(E) 6.8


Are You Up For the Challenge: 700 Level Questions


Attachment:
1b.jpg

EC/CA=ED/DB , what you have done with the similarity property is wrong

Posted from my mobile device

Originally posted by nick1816 on 06 Nov 2019, 01:17.
Last edited by nick1816 on 06 Nov 2019, 01:34, edited 1 time in total.
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Re: What is the length of hypotenuse k?  [#permalink]

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New post 06 Nov 2019, 01:30
2
Sorry nick, didnt pay much attention to the angle90degrees between two triangles so that makes one angle x and other angle 90-x right?so 90-x is between AC and CE, and DEand BE

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Re: What is the length of hypotenuse k?   [#permalink] 06 Nov 2019, 01:30
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