GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 19 Feb 2020, 23:14 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # What is the maximum value of x for which

Author Message
TAGS:

### Hide Tags

e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 3239
What is the maximum value of x for which  [#permalink]

### Show Tags 00:00

Difficulty:   15% (low)

Question Stats: 84% (01:25) correct 16% (01:28) wrong based on 81 sessions

### HideShow timer Statistics

Algerba Question Series- Question 2

What is the maximum value of x for which 8$$x^2$$ = 1 + 2x?

A. $$\frac{-1}{2}$$
B. $$\frac{-1}{4}$$
C. 0
D. $$\frac{1}{4}$$
E. $$\frac{1}{2}$$

_________________
Intern  S
Status: Classified
Joined: 19 Jun 2019
Posts: 33
Re: What is the maximum value of x for which  [#permalink]

### Show Tags

1
EgmatQuantExpert wrote:

Algerba Question Series- Question 2

What is the maximum value of x for which 8$$x^2$$ = 1 + 2x?

A. $$\frac{-1}{2}$$
B. $$\frac{-1}{4}$$
C. 0
D. $$\frac{1}{4}$$
E. $$\frac{1}{2}$$

\begin {alignat}{2} && 8x^2 = 1 + 2x \\ &\implies &8x^2 - 2x - 1 = 0 \\ &\implies &8x^2 - 4x + 2x -1 = 0 \\ &\implies &4x(2x - 1) + 1(2x - 1) = 0 \\ &\implies &(2x - 1)(4x + 1) = 0 \\ &\implies &x = \frac{1}{2} \text{ or } \frac{-1}{4} \end {alignat}

Maximum value of $$x$$ is $$\frac{1}{2}$$.
_________________
Best
e-GMAT Representative V
Joined: 04 Jan 2015
Posts: 3239
Re: What is the maximum value of x for which  [#permalink]

### Show Tags

Solution

Given:
• An equation, $$8x^2 = 1 + 2x$$

To find:
• The maximum value of x for which $$8x^2 = 1 + 2x$$

Approach and Working Out:
$$8x^2 = 1 + 2x$$
• $$8x^2 - 2x – 1 = 0$$
• $$8x^2 – 4x + 2x – 1 = 0$$
• 4x * (2x – 1) + 1 * (2x – 1) = 0
• (4x + 1) * (2x – 1) = 0

Thus, x = $$\frac{1}{2} or –\frac{1}{4}$$

Therefore, the maximum value of x for which $$8x^2 = 1 + 2x$$ is $$\frac{1}{2}$$

Hence, the correct answer is Option E.

_________________ Re: What is the maximum value of x for which   [#permalink] 05 Aug 2019, 20:58
Display posts from previous: Sort by

# What is the maximum value of x for which  