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# What is the mean of a, b, c, d, e, and f ?

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Math Expert
Joined: 02 Sep 2009
Posts: 58464
What is the mean of a, b, c, d, e, and f ?  [#permalink]

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31 Jan 2019, 01:14
00:00

Difficulty:

35% (medium)

Question Stats:

67% (00:38) correct 33% (01:12) wrong based on 23 sessions

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What is the mean of a, b, c, d, e, and f ?

(1) $$7a+5b+3c+4d+2e+6f=10,000$$

(2) $$2a+4b+6c+5d+7e+3f=8,000$$

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Re: What is the mean of a, b, c, d, e, and f ?  [#permalink]

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31 Jan 2019, 01:25
Individual statements are clearly insufficient.

Adding both 1 and 2 gives, 9(a+b+c+d+e+f) = 18000
Therefore, a+b+c+d+e+f = 2000

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Re: What is the mean of a, b, c, d, e, and f ?  [#permalink]

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31 Jan 2019, 01:31
Bunuel wrote:
What is the mean of a, b, c, d, e, and f ?

(1) $$7a+5b+3c+4d+2e+6f=10,000$$

(2) $$2a+4b+6c+5d+7e+3f=8,000$$

we are looking for mean of a,b,c,d,e,f.

Statement 1: clearly NOT sufficient.

Statement 2: The same as 1.

Combining :

Add both of the statements. both statements together sufficient.

9a + 9b + 9c + 9d + 9e + 9f = 18000

9(a + b + c + d + e + f) = 18000

a + b+ c + d+ e+ f = 2000

a + b+ c+ d+ e+f /6 = 2000/6

That's what we are looking for.

Re: What is the mean of a, b, c, d, e, and f ?   [#permalink] 31 Jan 2019, 01:31
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