Bunuel
GMAT CLUB TESTS' FRESH QUESTION:
{a, b, c, d}
What is the median of the list above?
(1) The product of no two elements of the list is negative
(2) The sum of the elements of the list is 0
M36-120
Official Solution:\(\{a, b, c, d\} \)
What is the median of the list above? (1) The product of no two elements of the list is negative
The above means that the product of numbers in all two-number groups possible from the list is 0 or positive: \(ab \geq 0\), \(ac \geq 0\), \(ad \geq 0\), \(bc \geq 0\), ...
Notice that the list cannot contain both positive and negative numbers because in this case positive*negative will give negative result.
We can have the following nine cases:
\(\{negative, \ negative, \ negative, \ negative \}\)
\(\{negative, \ negative, \ negative, \ 0 \}\)
\(\{negative, \ negative, \ 0, \ 0 \}\)
\(\{negative, \ 0, \ 0, \ 0 \}\)
\(\{0, \ 0, \ 0, \ 0 \}\)
\(\{0, \ 0, \ 0, \ positive \}\)
\(\{0, \ 0, \ positive , \ positive \}\)
\(\{0, \ positive , \ positive , \ positive \}\)
\(\{positive , \ positive , \ positive , \ positive \}\)
The median can be some negative number (for the first three cases), 0 (for the next three cases) or some positive number (for the last three cases). Not sufficient.
(2) The sum of the elements of the list is 0
The median of \(\{0, \ 0, \ 0, \ 0 \}\) is 0;
The median of \(\{-10, \ -1, \ 5, \ 6 \}\) is 2.
Not sufficient.
(1)+(2) From (1) we got that the list cannot contain both positive and negative numbers and from (2) we know that the sum of the numbers is 0, so all numbers must be 0, making the median also equal to 0. Sufficient.
OR just check which case from (1) gives the sum of 0. Only \(\{0, \ 0, \ 0, \ 0 \}\)! Sufficient.
Answer: C