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Bunuel
What is the number of seven digit integers, with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only?

(A) 55
(B) 66
(C) 77
(D) 88
(E) 99

Are You Up For the Challenge: 700 Level Questions: 700 Level Questions
Solution:

If two of the seven digits were 3, then the sum of the digits would be greater than 10. We can verify this by assuming all the remaining five digits are as small as possible, i.e. 1. Thus, the seven-digit integer contains either no 3s or one 3. It follows that we could have only the following two options:

1) five 1s, one 2 and one 3

2) four 1s and three 2s

The first option has 7! / 5! = 7 x 6 = 42 integers, and the second option has 7! / (4! x 3!) = (7 x 6 x 5) / (3 x 2) = 35 integers. Therefore, we have a total of 42 + 35 = 77 such integers.

Answer: C
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