stonecold wrote:

What is the remainder when 1990990900032 is divided by 32 ?

A) 16

B) 8

C) 4

D) 2

E) 0

For powers of 2 - A number ending in as many 0s as the exponent of 2 will be divisible by that power of 2.

e.g. 2^4 = 16

A number N ending in four 0s will be divisible by 16.

e.g. 2^5 = 32

A number N ending in five 0s will be divisible by 32.

and so on...

1990990900032 = 1990990900000 + 32

1990990900000 ends in five 0s so will be divisible by 32.

32 is divisible by 32.

So 1990990900032 will be divisible by 32. Remainder will be 0.

Answer (E)

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Karishma

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