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# What is the remainder when 6^x is divided by 10

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BSchool Forum Moderator
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What is the remainder when 6^x is divided by 10 [#permalink]

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28 Nov 2017, 11:14
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35% (medium)

Question Stats:

60% (00:24) correct 40% (00:31) wrong based on 58 sessions

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What is the remainder when $$6^x$$ is divided by 10?

1. x is a positive integer
2. x is a positive even integer

Source: Experts Global
[Reveal] Spoiler: OA

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Re: What is the remainder when 6^x is divided by 10 [#permalink]

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28 Nov 2017, 22:14
1 alone is sufficient. If X is 0, then the remainder is 1. In all other cases the remainder is 6

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What is the remainder when 6^x is divided by 10 [#permalink]

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28 Nov 2017, 22:29
pushpitkc wrote:
What is the remainder when $$6^x$$ is divided by 10?

1. x is a positive integer
2. x is a positive even integer

Source: Experts Global

Statement 1: x is a positive interger. Meaning X > 0 and is an Integer.

Now, $$(6)^P$$ (where P is a positive Integer) will always give the last digit as 6 and hence remainder will always remain 6. --> SUFFICIENT

Statement 2: This is just a filtered part of Statement 1. Meaning in Statement 1, I already said we will get a single solution for X > 0 and X as an integer. Now, this includes both even and Odd. This, Statement 2 is also sufficient.

Hence, D.
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Re: What is the remainder when 6^x is divided by 10 [#permalink]

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28 Nov 2017, 23:05
6 raised to any positive integer power will Always give an integer that ends in '6' (meaning the unit place digit of that number would be 6). So such an integer, when divided by 10, would always give a remainder 6.

Here, each statement alone suffices to tell us that last digit of 6^x would be 6, hence remainder would be 6.

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Re: What is the remainder when 6^x is divided by 10 [#permalink]

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29 Nov 2017, 10:00
I jumped to the conclusion after reading statement 1.

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Re: What is the remainder when 6^x is divided by 10   [#permalink] 29 Nov 2017, 10:00
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