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(A)

Condition (1): Since n+6 gives reminder 1 when divided by 3, n=3m+1. When divided by 3, this always gives reminder 1.

Condition (2): n^2= 3m+1 for all m.
n=√3m+1 should be a perfect square, but not all squares can be expressed in this form. Hence, inadequate information to make a conclusion on 'n'.

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the value of +ve integer n is to be determined
#1
when n+6 is divided by 3, the remainder is 1.
here n can be 1,4,7,10.. so on
we see that we get remainder 1 for all values of n ; sufficient
#2
when n^2 is divided by 3, the remainder is 1.
n=5,7,11
insufficient as remainder are 2,1
OPTION A ; sufficient


Bunuel
What is the remainder when positive integer n is divided by 3?

(1) when n+6 is divided by 3, the remainder is 1.

(2) when n^2 is divided by 3, the remainder is 1.


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