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Re: What is the reminder when the positive integer n is divided [#permalink]
JohnLewis1980 wrote:
What is the reminder when the positive integer n is divided by the postivie integer k, where k>1?

(1) n=(k+1)^3

(2) k=5

OA=A

Please, any explanation?

Thank you!

[Edited: the OA is A and not C]


I dont think OA can be A..

n=(K+1)^3, suppose K=2 then 3^3=27/3 remainder is 0..but if K=4, then 5^3/3 has a non-zero remainder..

I think C is the correct answer..
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Re: What is the reminder when the positive integer n is divided [#permalink]
mmm, it could be possible that the GMAT PrepSoft were wrong?

I attached an screen with the OA

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Reminder answer.JPG
Reminder answer.JPG [ 43.73 KiB | Viewed 1887 times ]

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Re: What is the reminder when the positive integer n is divided [#permalink]
nikhilpoddar wrote:
A


could you please post your explanation?

Thank you
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Re: What is the reminder when the positive integer n is divided [#permalink]
JohnLewis1980 wrote:
mmm, it could be possible that the GMAT PrepSoft were wrong?

I attached an screen with the OA

Cheers


OOPs...OA is Correct..

n=(K+1)^3, suppose n=3^3 then k=2 then remainder is 1..

you will always note that remainder is 1..

A is correct
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Re: What is the reminder when the positive integer n is divided [#permalink]
yes, now it's clearer

This kind of problem is easier to solve using a couple of examples

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Re: What is the reminder when the positive integer n is divided [#permalink]
From stmt1: n = k^2 + 2k + 1 and since the first two terms are divisible by k, the remainder will be 1. Hence, stmt 1 is sufficient.
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Re: What is the reminder when the positive integer n is divided [#permalink]
hi,
n=(k+1)3 and not (k+1)2 to break it into k^2 +2k+1.
however, (k+1)3 is k^3+1+3k^2+3k--[a^3 +b^3+3ab(a+b)]

the remainder will always be 1.
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Re: What is the reminder when the positive integer n is divided [#permalink]
scthakur wrote:
From stmt1: n = k^2 + 2k + 1 and since the first two terms are divisible by k, the remainder will be 1. Hence, stmt 1 is sufficient.


scthakur...how did you arrive at n = k^2 + 2k + 1 from n = (k+1)^3 ?
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Re: What is the reminder when the positive integer n is divided [#permalink]
Answer is A. The remanider is always 1. Reason being that (k+1)^3 = K^3+3k^2+2k+1. Hence k is common in all variable except 1. Hence 1 will always be the remainder.
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Re: What is the reminder when the positive integer n is divided [#permalink]
bigtreezl wrote:
scthakur wrote:
From stmt1: n = k^2 + 2k + 1 and since the first two terms are divisible by k, the remainder will be 1. Hence, stmt 1 is sufficient.


scthakur...how did you arrive at n = k^2 + 2k + 1 from n = (k+1)^3 ?


My fault. I wrongly read as (k+1)^2. But, even with k+1)^3, all the terms but the last will have k and hence the remainder will always be 1.



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