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01 Jul 2020, 10:28
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
(medium)
Question Stats:
72% (01:29) correct
28%
(01:35)
wrong
based on 206
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What is the result of adding the units digit of 2002^2002 to the units digit of 7007^7007?
(A) 1
(B) 4
(C) 5
(D) 7
(E) 9
(A) 1
(B) 4
(C) 5
(D) 7
(E) 9
01 Jul 2020, 10:33
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Explanation:
Using the concept of cyclicity;
2002^2002 = 2^2
= 4
7007^7007 = 7^7 = 7^3
= 3
Unit Digit = 4+3 = 7
IMO-D
Using the concept of cyclicity;
2002^2002 = 2^2
= 4
7007^7007 = 7^7 = 7^3
= 3
Unit Digit = 4+3 = 7
IMO-D
01 Jul 2020, 10:36
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Bunuel
What is the result of adding the units digit of 2002^2002 to the units digit of 7007^7007?
(A) 1
(B) 4
(C) 5
(D) 7
(E) 9
2002^4(500)+2(A) 1
(B) 4
(C) 5
(D) 7
(E) 9
2^[4(500)+2]
unit digit=4
7007^7007
7^[4(1751)+3]
7^4*7^3
unit digit=3
Sum=4+3
=7
D:)
