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705-805 Level|   Sequences|      
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Bunuel
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What is the smallest positive integer n, such that the sum of 2n terms 15 May 2020, 08:19
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85% (hard)

Question Stats:

51% (02:49) correct 49% (02:47) wrong based on 109 sessions

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Sequence A = {1, 5, 9, 13, ...}
Sequence B = {56, 58, 60, 62, ...}

What is the smallest positive integer n, such that the sum of 2n terms of sequence A is greater than the sum of n terms of sequence B?

A. 8
B. 9
C. 10
D. 12
E. 14


Are You Up For the Challenge: 700 Level Questions
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B
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What is the smallest positive integer n, such that the sum of 2n terms 15 May 2020, 08:45
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Bunuel
Sequence A = {1, 5, 9, 13, ...}
Sequence B = {56, 58, 60, 62, ...}

What is the smallest positive integer n, such that the sum of 2n terms of sequence A is greater than the sum of n terms of sequence B?

A. 8
B. 9
C. 10
D. 12
E. 14


Seq_A: \(S_{2n} = \frac{2n(2+(2n-1)4)}{2}\)

Seq_B: \(S_{n} = \frac{n(2*56+(n-1)2)}{2}\)

\(n(8n-2) > \frac{n(112 + 2n -2)}{2}\)

\(8n^2-2n > n(n +55)\)
\(8n^2-2n > n^2 + 55n\)
\(7n^2 > 57n\)
\(7n > 57\)
n = 9
Ans: B
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What is the smallest positive integer n, such that the sum of 2n terms 15 May 2020, 19:49
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Sequence A = {1, 5, 9, 13, ...} = 4*m+1, m = 0, 1, 2, ......n,......2n
Sequence B = {56, 58, 60, 62, ...} = 2*m+56, m = 0, 1, 2, ......n,......2n

Sum of 2n terms in
\(A_{2n} = [4*1+1] + [4*2+1] + .......... [4*2n+1]\)
\(A_{2n} = 4[1+2+.....2n] + [1+1+.......1 (2n times)] \)
\(A_{2n} = 4[\frac{2n(2n+1)}{2}] + 2n \)
\(A_{2n} = 4n(2n+1)+2n\)

Sum of n terms in B
\(B_n = 2*m+56 \)
\(B_n = [2*1+56] + [2*2+56]+......... [2*n+56] \)
\(B_n = 2*[1+2+.....n] + 56*n \)
\(B_n = 2*\frac{n(n+1)}{2}+56n \)

Now, A_2n > B_n
4n(2n+1)+2n >n(n+1)+56n
7n>51 ---> for n = 8, 7n is > 51
Answer is A
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What is the smallest positive integer n, such that the sum of 2n terms 15 May 2020, 21:01
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Bunuel
Sequence A = {1, 5, 9, 13, ...}
Sequence B = {56, 58, 60, 62, ...}

What is the smallest positive integer n, such that the sum of 2n terms of sequence A is greater than the sum of n terms of sequence B?

A. 8
B. 9
C. 10
D. 12
E. 14


Are You Up For the Challenge: 700 Level Questions

For sequence 1, a = 1, d =4.
For seq 2, a =56, d =2
We need to find, a + (2n -1) 4 > a +(n-1)2
or, 1 + 8n - 4 > 56 + 2n -2
or, 6n -3 > 54
or, 6n > 57
or, n > 9. something
so, the smallest possible integer n can take is 10.
C is the answer
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What is the smallest positive integer n, such that the sum of 2n terms 03 Mar 2025, 05:28
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