What is the sum of all numbers greater than 10000 formed by using the

We don't require to calculate the entire answer, as we can see that the UNIT's digit is different in each option..
If abcde is the number, then taking e as 1, we get 3 positions for a ( less 0 and the digit at e), and 3*2*1 for remaining three.
So, 3*3*2*1*1=18
Thus each of the digits 1, 2, 4 and 5 will come 18 times in the units digit.
The units digit of sum = 18*(1+2+4+5)=18*12...8*2=16

E is the answer.


If you want to find the exact answer.
abcde.
e : e will be the units digit of 18*12=216, so 6
d : Now 21 will get carried over to tens place and it will become 216+21=237, so 7
c : Again 23 will get carried over to hundreds place and it will become 216+23=239, so 9
b : Again 23 will get carried over to hundreds place and it will become 216+23=239, so 9
a : For a, the sum of digits will change, as it is restricted by only non-zero integers. Hence if 1 is at a position, other arrangements will be 4*3*2*1=24. So 24*(1+2+4+5)=24*12=288. But we have a carry over of 23. So 288+23=311

Number = 3119976