gmatophobia
nasgmatbag
At the time of solving this problem, there was no answer available. So I'm showing my steps in the hope that someone can confirm if I got this correct.
1) x + 3y = 21 -> tells that the second value (1932) = 1932^21, we could find the unit digit. The other value (435) will always have an unit digit of 5 no matter the exponent, so I saw this as sufficient since we could solve to find the unit digit
2) 2y - 6 = |y| -> in this case y could only be 6, since 12-6 = |6|. With this information we do not know the value of x in the prompt for 1932, hence insufficient
My answer: A
You're almost there
nasgmatbag
In your solution, you've assumed x as a positive integer. However, nothing on the question restricts us to use positive integers.
Hint: What if x = 0 (or negative), can we still conclude \(435^x\) will end in 5?
Hi
gmatophobia,
You're absolutely correct. I don't know why I've assumed that.. but with this information is the following correct?
1) x + 3y = 21 -> gives only the value of the second digit (1932), we cannot conclude anything from x and therefore the first digit, hence insufficient
2) 2y - 6 = |y| -> in this case y could only be 6, since 12-6 = |6|. With this information we do not know the value of x in the prompt for 1932, hence insufficient
1 & 2) -> since y = 6, we can conclude that x must be 3. Therefore when both statements are combined we can find the unit digit
Answer: C