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Abhi077
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Joined: 25 Sep 2018
Last visit: 18 Apr 2025
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Own Kudos:
Given Kudos: 1,665
Location: United States (CA)
Concentration: Finance, Strategy
Schools: Rotman '21 Jindal '21 Stern '21
GPA: 3.97
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27 Sep 2018, 12:03
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
25%
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Question Stats:
73% (01:39) correct
27%
(02:01)
wrong
based on 147
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What is the value of 3x^2 - 1.3x -0.9 when x=0.2
A)-3.38
B)-2.30
C)-1.04
D)-0.76
E)-0.04
A)-3.38
B)-2.30
C)-1.04
D)-0.76
E)-0.04
27 Sep 2018, 12:25
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Consider x as 2/10 for easy simplification.
Then 3\(x^2\) - 1.3x -0.9 becomes 3*\(\frac{4}{100}\)-1.3*\(\frac{2}{10}\)-0.9 = 12/100-2.6/10-0.9 = -104/100 = -1.04.
C is the answer.
Then 3\(x^2\) - 1.3x -0.9 becomes 3*\(\frac{4}{100}\)-1.3*\(\frac{2}{10}\)-0.9 = 12/100-2.6/10-0.9 = -104/100 = -1.04.
C is the answer.
02 Oct 2018, 19:34
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Abhi077
What is the value of 3x^2 - 1.3x -0.9 when x=0.2
A)-3.38
B)-2.30
C)-1.04
D)-0.76
E)-0.04
A)-3.38
B)-2.30
C)-1.04
D)-0.76
E)-0.04
Since x = 0.2 we have:
3(0.2^2) - 1.3(0.2) - 0.9
3 x 0.04 - 0.26 - 0.9
0.12 - 0.26 - 0.9 = -1.04
Answer: C
