sananoor
Hi everyone, how it will ended up in one value, can anyone explain this to me
To solve any question related to absolute value, you need to remember this rule:
\(|x| = x \) if \(x \geq 0\) and \(|x|= - x\) if \(x < 0\)
Now, the question asks for the value of \(|4−|3−x||\)
(1) \(|x−4|=6\)
This one leads to two possible outcomes:
Case 1: \(x-4 = 6 \implies x = 10.\)
Case 2: \(x-4=-6 \implies x=-2\)
From case 1, we have \(x=10 \implies |4−|3−x||=|4-|3-10||=|4-|-7||=|4-7|=|-3|=3\)
From case 2, we have \(x=-2 \implies |4−|3−x||=|4-|3-(-2)||=|4-|5||=|4-5|=|-1|=1\)
From this statement, we could have 2 possible values. Hence insufficient.
(2) |6−x|=4
The same way to solve this one, we have \(x=2\) or \(x=10\).
If \(x=10 \implies |4−|3−x|| = 3\)
If \(x=2 \implies |4−|3−x|| = 3\)
Now, from 2 possible cases, we could have only one possible value. Hence, sufficient.
Hope this helps