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Bunuel
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2x^2+6y=?; taking 2 common=>2(X^2+3Y)=?

1. Y is given but we can answer as we dont know value of x. Insufficient.
2. X^2+3Y =given, so we now the answer of the term as 36. Sufficient.

Hence Answer is B.

Thanks.
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initial assesment: orig cond : 2(x^2 + 3y)
likely ans is c.. but since c is too trivial, we look at a/b.

a : insuff
b: suff.

ANS :B
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Hi,

Option B is sufficient.
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we have to find the value of 6\(y\) + 2\(x^2\)
Statement 1 gives us \(y\) = 14
we don't have any information on \(x\) so insufficient
Statement 2 gives us \(x^2\) + 3\(y\) = 18
multiply by 2 we get 2\(x^2\) + 6\(y\) = 36 so sufficient
correct answer -\(B\)
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