greatchap
I first thought it could be solved by #1 also, and it took me some time to figure out that it cannot (certainly longer than 2 min!).
I took each equation and found in terms of each variable there.
\(x = \frac{y}{2}\) and \(y = 2x\)
\(z = \frac{2x}{5}\) and \(x = \frac{5z}{2}\)
Since we know \(y = 2x\), I also substituted this in for \(z = \frac{2x}{5}\) so \(z = \frac{y}{5}\) and \(y = 5z\).
Now since we know x in terms of z and y in terms of z, I substituted these values in for \(x=\frac{y}{2}\). This gives us :
\(\frac{5z}{2} = \frac{5z}{2}\) - this doesn't give us any new information about z because no matter what z is, it's identical on the other side. When we have 3 variables, we need 3 different equations to be able to solve with substituting.
jallenmorris
What is the value of \(\frac{x}{yz}\)?
(1) \(x = \frac{y}{2}\) and \(z = \frac{2x}{5}\)
(1) \(\frac{x}{z}\) = \(\frac{5}{2}\) and \(\frac{1}{y}\) = \(\frac{1}{10}\)