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What is the value of integer J? 1. |J|= J^-1 2.J^J=1

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What is the value of integer J? 1. |J|= J^-1 2.J^J=1 [#permalink]

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New post 03 Sep 2008, 14:21
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C
D
E

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What is the value of integer J?
1. |J|= J^-1
2.J^J=1

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient
Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient
BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient
EACH statement ALONE is sufficient
Statements (1) and (2) TOGETHER are NOT sufficient
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Last edited by x2suresh on 03 Sep 2008, 14:28, edited 1 time in total.

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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 14:27
where is the question?
I cannt see it.
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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 14:28
subarao wrote:
where is the question?
I cannt see it.


sorry updated.. copy paste problem
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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 17:07
B

J power J =1

Any thing raised to power 0 =1 but we clearly see that base and exponent has to be equal that means J=0 Sufficient

|J| =J power -1

mean J = 1/J & -J = 1/J

means J= 1/J = -1/J . Cannot happen. Insufficient

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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 20:27
D

statement 1: |J|= J^-1 ---> |J|= 1/J
1/J has to be positive, and can't be zero, thus J = 1
suff

statement 2: J^J=1, J has to be 1
suff

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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 20:53
Hmm! I guess I missed it badly.

J power J =1

0 power 0 =1 ( Is it 1 or not?? ) Read this http://en.wikipedia.org/wiki/Exponentia ... zero_power

1 power 1 =1

J=0/1 (2 values. B & D insufficient)

| J | = J power -1

J = 1/J ( J +ve) and J =-1/J ( J -ve)

Case 1) J is +ve

only value where J =1/J is J =1

case 2) J is -ve

No value such that J = -1/J

case 3) if J is 0 neither 1/J or -1/J is defined.

So Is the OA A?

Last edited by icandy on 03 Sep 2008, 22:02, edited 1 time in total.

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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 21:52
IMO D.

1. |J|= J^-1

|J| is always +ve or 0 ; so 1/J has to be +ve, as it can not be 0 => J^2=1=> J=1 ( as j is +ve)

2.J^J=1

only solution J= 1 ( 0^0 is not 1 )

So, each statement is sufficient.

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Re: DS -INTEGER [#permalink]

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New post 03 Sep 2008, 23:53
D.

Stmt1 : |J| = 1/J.....J cannot be 0. If J is -1 then left side is +ve but right side is -ve. Hence, only possible value of J is 1...sufficient.

Stmt 2: J^J = 1 => J cannot be zero. If J is -1 then left side will be -1...hence only possible value of J is 1. Sufficient.

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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 00:49
IMO A.

I am on thin ice here, but I think the GMAT does not give you 'undefined' values, so we can assume J is not zero. So:

1) J can only be 1. Sufficient.
2) J can be 1 or -1. Not sufficient.
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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 00:50
Ops. It is D. Didn't read the stem correctly.
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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 06:15
OA is D.

Thanks guys.

I missed 0^0 =undefined
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Last edited by x2suresh on 04 Sep 2008, 06:39, edited 2 times in total.

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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 06:28
x2suresh wrote:
OA is D.

Thanks guys.

I missed 0^0 =1 part.


But if you include 0 as a possible answer, then it should not be D? because in statement 2, it can be 0 or 1. What am I missing?

I excluded 0 form my answer, because in statement 1 we have J^-1. So I assumed J cannot be zero.
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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 06:29
Nerdboy wrote:
x2suresh wrote:
OA is D.

Thanks guys.

I missed 0^0 =1 part.


But if you include 0 as a possible answer, then it should not be D? because in statement 2, it can be 0 or 1. What am I missing?

I excluded 0 form my answer, because in statement 1 we have J^-1. So I assumed J cannot be zero.



I mean 0^0 is undefined. so its not possible value.

I updated the orignal post.
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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 06:36
x2suresh wrote:
OA is D.

Thanks guys.

I missed 0^0 =undefined part.



just a clarification.. so in gmat universe what should 0^0 be ? 1 or undefined ? In calculus and real number world, it is not necessarily 1.

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Re: DS -INTEGER [#permalink]

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New post 04 Sep 2008, 07:19
bhushangiri wrote:
x2suresh wrote:
OA is D.

Thanks guys.

I missed 0^0 =undefined part.



just a clarification.. so in gmat universe what should 0^0 be ? 1 or undefined ? In calculus and real number world, it is not necessarily 1.


Exactly! What is 0 power 0 in GMAT world?

x2suresh,

How did you decide that it is undefined? Can you please share any such info you may have?

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Re: DS -INTEGER   [#permalink] 04 Sep 2008, 07:19
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What is the value of integer J? 1. |J|= J^-1 2.J^J=1

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